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Re: Lines Intersection [#permalink]
31 Oct 2009, 23:38
Expert's post
gmattokyo wrote:
Please see the image for the Q and options...
I think there must be a typo in line 2 definition. Line should be represented as equation. y2-4x+6 shoul be equal to something, in the way it's represented it doesn't make any sense for me. Let's find out which kind of typo there is:
y2-4x+6?
1. y1=5x-3, y2=4x+6 (meaning that - sign should be =): 5x-3=4x+6 --> x=9, y=42 --> intersect at point (9,42), no such answer choice.
2. y1=5x-3, y2-4x+6=0 (meaning that LHS equals to 0): 5x-3=4x-6 --> x=-3, y=-18 --> intersect at point (-3,-18), no such answer choice.
3. y1=5x-3, y2=-4x+6 (meaning that = sign is just missing) 5x-3=-4x+6 --> x=1, y=2 --> intersect at point (1,2), answer choice D.
So, I suppose the third option detects the typo. But it would be easier if we knew the OA to say with certainty. _________________
Re: Lines Intersection [#permalink]
31 Oct 2009, 23:50
Bunuel wrote:
gmattokyo wrote:
Please see the image for the Q and options...
I think there must be a typo in line 2 definition. Line should be represented as equation. y2-4x+6 shoul be equal to something, in the way it's represented it doesn't make any sense for me. Let's find out which kind of typo there is:
y2-4x+6?
1. y1=5x-3, y2=4x+6 (meaning that - sign should be =): 5x-3=4x+6 --> x=9, y=42 --> intersect at point (9,42), no such answer choice.
2. y1=5x-3, y2-4x+6=0 (meaning that LHS equals to 0): 5x-3=4x-6 --> x=-3, y=-18 --> intersect at point (-3,-18), no such answer choice.
3. y1=5x-3, y2=-4x+6 (meaning that = sign is just missing) 5x-3=-4x+6 --> x=1, y=2 --> intersect at point (1,2), answer choice D.
So, I suppose the third option detects the typo. But it would be easier if we knew the OA to say with certainty.
yes, there was a typo in the first image equal sign was missing... thnx for pointing that out. You got this nailed.
Re: Lines Intersection [#permalink]
06 Nov 2012, 19:50
1
This post received KUDOS
Since at the point of intersection, the two equations will have the same values of x and y, we set the two equations equal to each other. This gives an equation that we can solve for x We substitute that x value in one of the line equations (it doesn't matter which) and solve it for y.
y1 = 5x - 3 y2 = -4x+6
At intersection point, y1 = y2 5x - 3 = -4x + 6 x = 1
By substituting value of x in any of the above 2 equations we get y = 5*1 - 3 y = 2
Re: At which point do the lines y1 = 5x - 3 and y2 = -4x + 6 [#permalink]
01 May 2015, 07:16
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Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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Re: At which point do the lines y1 = 5x - 3 and y2 = -4x + 6 [#permalink]
07 May 2015, 20:57
Expert's post
Hi All,
In these types of questions, since the answer choices ARE co-ordinates, we just need to find the one co-ordinate that "fits" both equations.
Y = 5X - 3 and Y = -4X + 6
Answer A: (1/3, 14/3) - does NOT fit the first equation. Answer B: (1/3, 22/3) - does NOT fit the first or second equation. Answer C: (1, -2) - does NOT fit the first or second equation Answer D: (1, 2) - Fits BOTH equations Answer E: (3, -6) - no need to check this one (but it does NOT fit the first equation.
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