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Attached are 2 questions i am not sure how to get to the

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Attached are 2 questions i am not sure how to get to the [#permalink] New post 03 Feb 2007, 09:59
Attached are 2 questions i am not sure how to get to the right answer. Can anyone help?

Thanks!!!!!! :o
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 [#permalink] New post 03 Feb 2007, 10:39
For the first one:

5^21 * 4^11 = 2 * 10^n

5^21 * (2^2)11 = 2 * 10^n

5^21 * 2^22 = 2 * 10^n

5^21 * 2^21 * 2 = 2* 10^n

2 * 10^21 = 2 * 10^n

Hence n=21

For the second one:

You can select 2 men out of 4 in 4C2 ways = 6

You can select 2 women out of 3 in 3C2 ways = 3

And the number of task force formed by 2 men and 2 women = 6*3 = 18
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 [#permalink] New post 03 Feb 2007, 10:40
Solution to first one
5^21 * 4^11 =2 *10^n
5^21 * 4 *4^10/2=10^n
5*5^20 *2*2^20=10^n
10 *10^20=10^n
10^21=10^n
n =21

Solution to second one
4c2*3c2
  [#permalink] 03 Feb 2007, 10:40
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Attached are 2 questions i am not sure how to get to the

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