Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 25 Jun 2016, 07:43

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Attached - have fun

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
VP
Joined: 08 Jun 2005
Posts: 1146
Followers: 6

Kudos [?]: 164 [0], given: 0

Attached - have fun [#permalink]

### Show Tags

26 Oct 2007, 04:56
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Attached - have fun !

Attachments

untitled.GIF [ 9.21 KiB | Viewed 722 times ]

SVP
Joined: 01 May 2006
Posts: 1798
Followers: 9

Kudos [?]: 132 [0], given: 0

[#permalink]

### Show Tags

26 Oct 2007, 05:38
(A) too

If BQ = CR = DS = AP, then the shapes of the 4 pieces are the same. That implies PR and QS are composed of 1 long and 1 small "interior" sides.

And so, PR = QS.

The fact that we know the perimeter is useless...
Director
Joined: 09 Aug 2006
Posts: 763
Followers: 1

Kudos [?]: 147 [0], given: 0

[#permalink]

### Show Tags

26 Oct 2007, 06:38
Fig wrote:
(A) too

If BQ = CR = DS = AP, then the shapes of the 4 pieces are the same. That implies PR and QS are composed of 1 long and 1 small "interior" sides.

And so, PR = QS.

The fact that we know the perimeter is useless...

Fig, can you pls. explain how you go from 'BQ = CR = DS = AP' to 'the shapes of the 4 pieces are the same'

If BQ = CR = DS = AP, then QC = RD = AS = PB, since it is a square. How do you proceed from here?
Manager
Joined: 21 Feb 2007
Posts: 81
Followers: 1

Kudos [?]: 3 [0], given: 0

[#permalink]

### Show Tags

26 Oct 2007, 07:00
Ans A
Since BQ = CR = SD = AP ;
As sides of a square are equal :
PB = AS = DR = QC
Again each angle i.e B , C , D , A must be 90(angles of a square)
hence their opp angles must be 90. So figures are actually rectangles with PR = QS
SVP
Joined: 01 May 2006
Posts: 1798
Followers: 9

Kudos [?]: 132 [1] , given: 0

[#permalink]

### Show Tags

26 Oct 2007, 07:03
1
This post received
KUDOS
GK_Gmat wrote:
Fig wrote:
(A) too

If BQ = CR = DS = AP, then the shapes of the 4 pieces are the same. That implies PR and QS are composed of 1 long and 1 small "interior" sides.

And so, PR = QS.

The fact that we know the perimeter is useless...

Fig, can you pls. explain how you go from 'BQ = CR = DS = AP' to 'the shapes of the 4 pieces are the same'

If BQ = CR = DS = AP, then QC = RD = AS = PB, since it is a square. How do you proceed from here?

Well, I can try

As BQ = CR = DS = AP, we know that QC = RD = SA = BP because we have a square with each side thus equal.

Then, at this point, we know that the triangles BQP, QCR, RDS and SAP are right similar triangles.

That implies that PQ=QR=RS=SP.

In addition, each angle of PQRS are rights by the following reasonning:
o angle(PQR) = 180 - angle(BQP) - angle(RQC)
= 180 - (90-angle(BPQ)) - angle(RQC) as BQP is a right triangle
= 90 + angle(BPQ) - angle(RQC)
= 90 + angle(BPQ) - angle(BPQ) as BPQ and RQC are similar triangles
= 90

We are thus now with PQRS definied by:
o 4 equal sides
o 4 right angles

It's the definition of a square and that means its diagonals PR and QS are equal.

Last edited by Fig on 26 Oct 2007, 07:07, edited 1 time in total.
SVP
Joined: 01 May 2006
Posts: 1798
Followers: 9

Kudos [?]: 132 [0], given: 0

[#permalink]

### Show Tags

26 Oct 2007, 07:04
abiswas wrote:
Ans A
Since BQ = CR = SD = AP ;
As sides of a square are equal :
PB = AS = DR = QC
Again each angle i.e B , C , D , A must be 90(angles of a square)
hence their opp angles must be 90. So figures are actually rectangles with PR = QS

Faster taped than I did
VP
Joined: 08 Jun 2005
Posts: 1146
Followers: 6

Kudos [?]: 164 [0], given: 0

[#permalink]

### Show Tags

26 Oct 2007, 08:48
the OA is (A)

[#permalink] 26 Oct 2007, 08:48
Display posts from previous: Sort by

# Attached - have fun

 post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.