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Aunt Marge has 20 pieces of candy to disperse among her

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Aunt Marge has 20 pieces of candy to disperse among her [#permalink] New post 13 Nov 2007, 14:14
Aunt Marge has 20 pieces of candy to disperse among her nephews and nieces.

R gets 2 more than K
B gets 6 less than M
M gets 2 more than R
K gets 2 more than B

How many does K get?
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 [#permalink] New post 13 Nov 2007, 14:19
b m k r
x-4 x+2 x-2 x


4x-4 = 20

x = 4

k = 2
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 [#permalink] New post 13 Nov 2007, 17:40
The answer is 4

R = K + 2
B = M - 6
M = R + 2
K = B + 2

So it will
B K R M

if B gets x, we can see that the difference is 2 between each
x + (x+2) + (x+4) + (x+6) = 20
Solve for x = 2

So K = x+2 = 4
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Re: easy algebra - aunt marge [#permalink] New post 13 Nov 2007, 18:03
bmwhype2 wrote:
Aunt Marge has 20 pieces of candy to disperse among her nephews and nieces.

R gets 2 more than K
B gets 6 less than M
M gets 2 more than R
K gets 2 more than B

How many does K get?


R=k+2
b=m-6--> b=k-2
M=2+r--> m=4+k
k=2+b

r+b+k+m=20
2k+2+2k+2=20
4k=16
k=4
Re: easy algebra - aunt marge   [#permalink] 13 Nov 2007, 18:03
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