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I have a question:
Why did we take the Number of marbles in BAG A and BAG B to be equal as K? It did not state in the question?
I both were different quantities they would be slit up as : 2x : 6x: 9 x
and BAG B as : 1y : 4y
then i took 6x + 4 y = 30 3x + 2y = 15
i took y = 1 x = 13/3 not possible y = 2 x = 11/3 not possible y = 3 x = 3 possible.
So i since x = 3 i got R = 6. Is my approach correct.
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tkarthi4u wrote: I have a question:
Why did we take the Number of marbles in BAG A and BAG B to be equal as K? It did not state in the question?
I both were different quantities they would be slit up as : 2x : 6x: 9 x
and BAG B as : 1y : 4y
then i took 6x + 4 y = 30 3x + 2y = 15
i took y = 1 x = 13/3 not possible y = 2 x = 11/3 not possible y = 3 x = 3 possible.
So i since x = 3 i got R = 6. Is my approach correct. because 30 is the quantity from both bags, you can use the same variable; i.e. 6x+4x=30, x=3. then use this ratio for both bags.
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I highly doubt that. I proceeded the same way as tkarthi. I dont think you can add two distinct ratios together.
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Bag A contains red, white and blue marbles such that the red to white marble ratio is 1:3 and the white to blue marble ratio is 2:3. Bag B contains red and white marbles in the ratio of 1:4. Together, the two bags contain 30 white marbles. How many red marbles could be in bag A? 1 3 4 6 8 D
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Re: Ratio of Marbles [#permalink]
02 Jun 2009, 08:45
Combined Ratio of marbles in
Bag A \Rightarrow 2:6:9 \Rightarrow a multiple of 6. Let the while marbles = 6x
Let White marbles in Bag B = W_b
Let White marbles in Bag A = W_a
Let Red marbles in Bag A = R_a
Bag B has (30-6x), which is a multiple of 4.
If x = 1, W_b = 24, W_a = 6, \Rightarrow R_a = 2 , which is not in the solution.
If x = 2, (30-12) is not a multiple of 4
If x = 3, W_b = 12, W_a = 18, \Rightarrow R_a = 6 , which is IN the solution.
If x = 4, (30-24) is not a multiple of 4.
Thus, answer is D.
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Bag A contains red, white and blue marbles such that the red to white marble ratio is 1:3 and the white to blue marble ratio is 2:3. Bag B contains red and white marbles in the ratio of 1:4. Together, the two bags contain 30 white marbles. How many red marbles could be in bag A? 1 3 4 6 8 MGMAT/CAT1/Ratios/PS
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Bag A contains red, white and blue marbles such that the red to white marble ratio is 1:3 and the white to blue marble ratio is 2:3. Bag B contains red and white marbles in the ratio of 1:4. Together, the two bags contain 30 white marbles. How many red marbles could be in bag A?
1 3 4 6 8
Solution - Combined ratio of Red:White:Blue marbles in bag A is 2:6:9.
And ratio of Red:White in Bag B = 1:4
So total white marbled in 2 bags combined = 30 (given) => 6x + 4x = 30 => x = 3
Hence red marbles in Bag A = 2x = 2*3 = 6
I would go with D. Whats the OA?
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Answer is D.
SdRandom, there is an error in your solution.
Your ratios are right. 2/6/9 in A 1/4 in B That makes 6x + 4y=30 This is where you have done wrong. After it. We must look at the choices. Red no's must be even (2/6/9 ratio) So it may be 4, 6 or 8. If red is 4 => whites in A becomes 12; whites in B becomes 18 (30-12) => 1/4 ratio becomes impossible thus 4 is wrong. If red is 8 => whites in A becomes 24; whites in B becomes 6 => 1/4 ratio becomes impossible When red is 6 => whites in A becomes 18; in B becomes 12 thus 1/4 ratio becomes possible
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Is my process correct? A R:W:B =2:6:9 B R:W=1:4 Now.A+B has 30 white marbles. Out of this 30 B has 4/5 x 30 = 24 marbles,therefore the rest 30-24=6 must be from A.  Hence,D.
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ALSO Bag A contains red, white and blue marbles such that the red to white marble ratio is 1:3 and the white to blue marble ratio is 2:3. Bag B contains red and white marbles in the ratio of 1:4. Together, the two bags contain 30 white marbles. How many red marbles could be in bag A? A) 1 B) 3 C) 4 D) 6 E) 8 Please explain. I did not understand the explanation given. Thanks
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Re: help please :) [#permalink]
29 Aug 2010, 15:47
Already posted: marbel-ratios-80692.htmlPlease search in the future. Locked.
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Re: help please :) [#permalink]
29 Aug 2010, 15:49
sorry! This probably sounds stupid but I didnt know that we can search questions. Thanks!
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Re: help please :) [#permalink]
29 Aug 2010, 17:54
spatel121990 wrote: ALSO Bag A contains red, white and blue marbles such that the red to white marble ratio is 1:3 and the white to blue marble ratio is 2:3. Bag B contains red and white marbles in the ratio of 1:4. Together, the two bags contain 30 white marbles. How many red marbles could be in bag A? A) 1 B) 3 C) 4 D) 6 E) 8 Please explain. I did not understand the explanation given. Thanks  BAG A: R to W to B is 2 to 6 to 9 BAG B: R W is 1 to 4 white in both is 30 therefore using 4+6 = 10 30/10 = 3 therefore 3 *6 = 18 white in bag a ration is 2 to 6 therefore if 18w, 18*2/6 = 6red D
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MGMT ratio problem [#permalink]
02 Aug 2011, 22:38
Bag A contains red, white and blue marbles such that the red to white marble ratio is 1:3 and the white to blue marble ratio is 2:3. Bag B contains red and white marbles in the ratio of 1:4. Together, the two bags contain 30 white marbles. How many red marbles could be in bag A? 1 3 4 6 8 Bag A: R/w = 1/3 and w/b=2/3 Bag B: R/w = 1/4 Number of White marbles in A and B is 30 . i.e A+B =30 so in Bag B Number of white marbles will be 30/5 * 4 = 24 since A+B = 30 => B= 24 then in Bag A number of white marbles will be 6 Now R/w = 1/3 => R/6 = 1/3 => R=2But there is NO 2. what i'm doing wrong. please explain. regards
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Re: MGMT ratio problem [#permalink]
02 Aug 2011, 22:59
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shrive555 wrote: Bag A contains red, white and blue marbles such that the red to white marble ratio is 1:3 and the white to blue marble ratio is 2:3. Bag B contains red and white marbles in the ratio of 1:4. Together, the two bags contain 30 white marbles. How many red marbles could be in bag A? 1 3 4 6 8
Bag A: R:W:B|R:W:B 1x:3x:-|2x:6x:- -:2x:3x|-:6x:9x Bag A: R:W:B 2x:6x:9x Bag B: R:W 1y:4y If we just consider white marbles now: 6x+4y=30 y=(30-6x)/4 So, x=1; y=6 x=2; y=Non integer. Ignore x=3; y=3 x=4; y=Non integer x=5; y=0(Not possible) Thus, x can be either 1 or 3. If x=1; Bag A: R:W:B 2x:6x:9x R=2*1=2 If x=3; R=2*3=6 So, both 2 and 6 are possible numbers of red marbles in Bag A. Ans: "D"
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Re: MGMT ratio problem [#permalink]
02 Aug 2011, 23:14
fluke wrote: shrive555 wrote: Bag A contains red, white and blue marbles such that the red to white marble ratio is 1:3 and the white to blue marble ratio is 2:3. Bag B contains red and white marbles in the ratio of 1:4. Together, the two bags contain 30 white marbles. How many red marbles could be in bag A? 1 3 4 6 8
Bag A: R:W:B|R:W:B 1x:3x:-|2x:6x:- -:2x:3x|-:6x:9x Bag A: R:W:B 2x:6x:9xBag B: R:W 1y:4y If we just consider white marbles now: 6x+4y=30 y=(30-6x)/4 So, x=1; y=6 x=2; y=Non integer. Ignore x=3; y=3 x=4; y=Non integer x=5; y=0(Not possible) Thus, x can be either 1 or 3. If x=1; Bag A: R:W:B 2x:6x:9x R=2*1=2 If x=3; R=2*3=6 So, both 2 and 6 are possible numbers of red marbles in Bag A. Ans: "D" Thank you for your detail explanation. just little confusion. how did you get the red part. because i have to solve it through making equations R/w = 1/3 w/b=2/3 => R/b = 2/9 after this i don't know how to set up R:W:B I assume that you have used some short cut.
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Re: MGMT ratio problem [#permalink]
02 Aug 2011, 23:22
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shrive555 wrote: Thank you for your detail explanation. just little confusion. how did you get the red part. because i have to solve it through making equations R/w = 1/3 w/b=2/3 => R/b = 2/9 after this i don't know how to set up R:W:B I assume that you have used some short cut.  Not really; Just take the LCM of the common term: R:W=1:3 --------1 W:B=2:3 --------2 Here W is common; Take the LCM of 2,3=6 So, eq 1 needs to be multiplied by 2: R:W=(1:3)*2=2:6---------3 So, eq 2 needs to be multiplied by 3: W:B=(2:3)*3=6:9---------4 Now; 3 and 4 are both 6 whites; we can join them R:W:B 2:6:9
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Re: MGMT ratio problem [#permalink]
03 Aug 2011, 09:00
you guys are very much right 2 / 6 are the options possible
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Re: MGMT ratio problem [#permalink]
03 Aug 2011, 13:03
good question .. Bag A R:W:B = 2x: 6x: 9x and Bag B R:W = y:4y
6x + 4y = 30 => 3x + 2y = 15 ..
the only +ve integers that satisfy the above is 1, 6 and 3, 3 ..
red marbles in Bag A = 2x = 2 or 6 => answer is D
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Bag A contains red, white and blue marbles such that the red to white marble ratio is 1:3 and the white to blue marble ratio is 2:3. Bag B contains red and white marbles in the ratio of 1:4. Together, the two bags contain 30 white marbles. How many [highlight]red marbles could be in bag A[/highlight]? [/[color=#40FF00]color] a 1 b 3 c 4 d 6 e 8
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