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ball bounce question

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2 KUDOS received
Intern
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Joined: 02 Oct 2012
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ball bounce question [#permalink] New post 18 Oct 2012, 23:53
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Hi,

A ball is dropped from the height of X meters and it bounces back to x/3 meters and also moves ahead by y meters .
So how much distance will it cover as a total (up and move ahead) in Z bounces.


Please help
Intern
Intern
Joined: 19 Oct 2012
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Re: ball bounce question [#permalink] New post 19 Oct 2012, 00:20
Good question but please share answer with mee too
svarmit wrote:
Hi,

A ball is dropped from the height of X meters and it bounces back to x/3 meters and also moves ahead by y meters .
So how much distance will it cover as a total (up and move ahead) in Z bounces.


Please help
1 KUDOS received
Director
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Status: Done with formalities.. and back..
Joined: 15 Sep 2012
Posts: 645
Location: India
Concentration: Strategy, General Management
Schools: Olin - Wash U - Class of 2015
WE: Information Technology (Computer Software)
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Re: ball bounce question [#permalink] New post 19 Oct 2012, 00:40
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KUDOS
svarmit wrote:
Hi,

A ball is dropped from the height of X meters and it bounces back to x/3 meters and also moves ahead by y meters .
So how much distance will it cover as a total (up and move ahead) in Z bounces.


Please help


Couple of points before moving to solution

1. Wrong forum to post this question.
2. specify distance as total -
a. do you mean final displacement
b. or if u need total distance travelled - assumption on trajectory of the balls needs to be made (trajectory can be straight line, forming an eventual angle, or curve)
Without these can not be answered fully.


With the given information though -

Horizontal movement in n step = ny
Veritcal movement in nth step =x*3^-n
Total vertical movement (up) in n steps = summation of x*3^-k, from k=1 to n
Total vertical movement (up and down) in n steps = summation of x*3^-k + summation of x*3^-(k-1) *x, from k=1 to n


Hope it helps.. Definitely not a GMAT question :P
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Black Friday Debrief

Re: ball bounce question   [#permalink] 19 Oct 2012, 00:40
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