A ball is dropped from the height of X meters and it bounces back to x/3 meters and also moves ahead by y meters .
So how much distance will it cover as a total (up and move ahead) in Z bounces.
Couple of points before moving to solution
1. Wrong forum to post this question.
2. specify distance as total -
a. do you mean final displacement
b. or if u need total distance travelled - assumption on trajectory of the balls needs to be made (trajectory can be straight line, forming an eventual angle, or curve)
Without these can not be answered fully. With the given information though -
Horizontal movement in n step = ny
Veritcal movement in nth step =x*3^-n
Total vertical movement (up) in n steps = summation of x*3^-k, from k=1 to n
Total vertical movement (up and down) in n steps = summation of x*3^-k + summation of x*3^-(k-1) *x, from k=1 to n
Hope it helps.. Definitely not a GMAT question
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