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Baseball team consists of 20 players, 5 of whom are pitchers

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Intern
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Baseball team consists of 20 players, 5 of whom are pitchers [#permalink] New post 23 Apr 2005, 17:49
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Baseball team consists of 20 players, 5 of whom are pitchers and 15 position players. If the batting order consists of 8 differnet position players and 1 pticher, and if the pitcher is always last in the order, then how many different batting orders are there for this baseball team?
Manager
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 [#permalink] New post 23 Apr 2005, 21:35
We are picking ordered combinations of 8 from 15.
It is 8P15 = 15!/(15-8)!
For each ordered combination we are independetly picking one out of 5 pitchers.

X = 5 * 15! / 7!
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 [#permalink] New post 25 Apr 2005, 18:43
Agree with Tyr

my "old-school" method :P : (15*14*13*12*11*10*9*8)*5
which is the same than 15!*5/7! :wink:
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Re: COmbination 2 [#permalink] New post 26 Apr 2005, 07:40
rc1979 wrote:
Baseball team consists of 20 players, 5 of whom are pitchers and 15 position players. If the batting order consists of 8 differnet position players and 1 pticher, and if the pitcher is always last in the order, then how many different batting orders are there for this baseball team?

Just to clarify incase the question was how many different teams can be selected then we would use 15C8 instead of 15P8 right?
Re: COmbination 2   [#permalink] 26 Apr 2005, 07:40
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Baseball team consists of 20 players, 5 of whom are pitchers

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