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# Before you spend too much time on this one - be warned - I

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Manager
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Before you spend too much time on this one - be warned - I [#permalink]

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22 May 2007, 10:38
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Before you spend too much time on this one - be warned - I don't think the correct answer is amoung the choices; I could be wrong.

Together Andrea and Brian weigh p pounds. Brian weighs 10 pounds more than andrea. Brian and Andrea's dog, Cubby, weighs p/4 more pounds than andrea. In terms of p what is Cubby's weight in pounds?

a (p/2) -10
b (3p/4) -5
c (3p/2)-5
d (5p/4)-10
e 5p-5
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Re: PR BIN 4 Errata? [#permalink]

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22 May 2007, 10:54
gmatiscoming wrote:
Before you spend too much time on this one - be warned - I don't think the correct answer is amoung the choices; I could be wrong.

Together Andrea and Brian weigh p pounds. Brian weighs 10 pounds more than andrea. Brian and Andrea's dog, Cubby, weighs p/4 more pounds than andrea. In terms of p what is Cubby's weight in pounds?

a (p/2) -10
b (3p/4) -5
c (3p/2)-5
d (5p/4)-10
e 5p-5

A+B=P
B=A+10
B+C=A+P/4

2A+10=P A=(P-10)/2

C=(P-10)/2+P/4-(P-10)/2-10

C=P/4-10
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Re: PR BIN 4 Errata? [#permalink]

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22 May 2007, 11:17
gmatiscoming wrote:
Before you spend too much time on this one - be warned - I don't think the correct answer is amoung the choices; I could be wrong.

Together Andrea and Brian weigh p pounds. Brian weighs 10 pounds more than andrea. Brian and Andrea's dog, Cubby, weighs p/4 more pounds than andrea. In terms of p what is Cubby's weight in pounds?

a (p/2) -10
b (3p/4) -5
c (3p/2)-5
d (5p/4)-10
e 5p-5

A + B = P
B = A + 10
C= A + P/4

By substituting B in the second equation into the first equation, we get:

A + A + 10 = P ==> 2A + 10 = P ==> A = (P-10)/2

Substitute this A into the third equation

C = (P-10)/2 + P/4

Multiply the first value by 2 to get common denominators

C = (2P-20)/4 + P/4

Multiply both sides by 4

4C = 2P-20 + P
4C = 3P-20
C = 3P/4 - 5

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22 May 2007, 11:51

[1] A+B=p
[2] B=A+10
[3] C=(p/4)+A

Now, plug eq. [2] into eq. [1]:

A+A+10=p
2A+10=p
2A=p-10
A=(p/2)-5

Now plug this new eq. into eq. [3]:

C=(p/4)+(p/2)-5
C=(p/4)+(2p/4)-5
C=(3p/4)-5

What's the OA?
Manager
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22 May 2007, 13:03
they list the OA as B; but I took the line Brian and (+) Cubby weigh p/4 more than Andrea to mean:

B+C=A +p/4

which gives you an answer choice that isn't available. I guess I need to be more careful... ??
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22 May 2007, 13:54
Gmatiscoming congratulations ! I believe that you found a mistake in PR !!!

I have the PR and the mistake clearly comes from Cubby weight. The official explanation states that Cubby weight is P/4 punds more then Andrea while the stem clearly states that Brain and Cubby togther whigh P/4 more then Andrea !!! .

should I E-Mail PR ?

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22 May 2007, 22:01
Is PR's wording really wrong ?

It clearly says " Brian and Andrea's dog, C....., weighs (Singular & not plural).......tricky language , isn't it ?
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22 May 2007, 22:45
vidyasagar wrote:
Is PR's wording really wrong ?

It clearly says " Brian and Andrea's dog, C....., weighs (Singular & not plural).......tricky language , isn't it ?

If that's singular , why does it mention Brian ? should say "Andrea's dog, C....., weighs".

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23 May 2007, 21:30
I never even thought to think of singular vs. plural on this question... i guess you really have to be careful on the GMAT; but the line says "Brian and Andrea's dog, Cubby, weighs p/4"

so this almost becomes a grammar question too. but, shouldn't it be
"Brian and Andrea's dog each weigh p/4 pounds more than Andrea"???
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23 May 2007, 22:12
i got: (p/4) - 10.........

i think the answer isn't there.
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24 May 2007, 05:03
i got B....... took me 30 secs........
its easy guys........

A=P-B
B=A+10
C=A+ P/4

we need C.........
so, find A in terms of p.......
substitute value of B in first eq......

=> A=(P-10)/2
put the value of A in third eq......... and simplify.........
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24 May 2007, 07:11
devansh_god wrote:
i got B....... took me 30 secs........
its easy guys........

A=P-B
B=A+10
C=A+ P/4

we need C.........
so, find A in terms of p.......
substitute value of B in first eq......

=> A=(P-10)/2
put the value of A in third eq......... and simplify.........

quote "Brian and Andrea's dog, Cubby, weighs p/4 more pounds than andrea.."

C=A+ P/4 , does not compute !

should have been "Brian and Andrea's" dog, Cubby, weighs p/4 more pounds than andrea.."

Last edited by KillerSquirrel on 24 May 2007, 12:25, edited 1 time in total.
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Re: PR BIN 4 Errata? [#permalink]

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24 May 2007, 07:15
gmatiscoming wrote:
Before you spend too much time on this one - be warned - I don't think the correct answer is amoung the choices; I could be wrong.

Together Andrea and Brian weigh p pounds. Brian weighs 10 pounds more than andrea. Brian and Andrea's dog, Cubby, weighs p/4 more pounds than andrea. In terms of p what is Cubby's weight in pounds?

a (p/2) -10
b (3p/4) -5
c (3p/2)-5
d (5p/4)-10
e 5p-5

Solve from the options.

put (3p/4) - 5 = A + (p/4)

Solve for A and B and then see which equations satisfies A + B = P
Re: PR BIN 4 Errata?   [#permalink] 24 May 2007, 07:15
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