If i'm reading it right the question says how many combinations without ben and Ann. So the answer would be 5C4
I agree with Rich. If I understood the question correctly, then 5C4 must be the answer.
yeah, 5is correct
but can you tell me what i did wrong here..
i thought something like this
Total # of ways = 7C4
Consider cases where ben and ann are always present...so we have only 2 people to select from the remaining five
Thats how I got 5C2
so the # of cases where both are not present = 7C4 - 5C2
i cant spot the mistake...please clarify