I get 5 as well.
7!/4!3! = 35 number of ways w/ no constraints.
Now we have VWXYZAB
There are 5!/4!1! ways to arrange VWXYZ into groups of 4.
So its just 5.
Now can someone show me a method of getting the number of ways w/ A and B using combinations??? I cant figure it out. (Not using the above method to find out that its 30).
Ben and Ann are among 7 contestants from which 4 semifinalists are to be selected. Of the different possible selections, how many contain both
Ben and Ann?
if B and A are in it, then we only have to choose 2 of 5 people.
1*1*5C2 / 7c4
You tried your best and you failed miserably. The lesson is 'never try'. -Homer Simpson