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Bob just filled his car's gas tank with 20 gallons of [#permalink]
 18 May 2007, 16:38
Question Stats:
59% (02:33) correct
40% (01:23) wrong based on 149 sessions
Bob just filled his car's gas tank with 20 gallons of gasohol, a mixture consisting of 5% ethanol and 95% gasoline. If his car runs best on a mixture consisting of 10% ethanol and 90% gasoline, how many gallons of ethanol must he add into the gas tank for his car to achieve optimum performance? A. 9/10 B. 1 C. 10/9 D. 20/19 E. 2
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Re: Word Problem - chemical mixture [#permalink]
18 May 2007, 21:35
above720 wrote: Bob just filled his car's gas tank with 20 gallons of gasohol, a mixture consisting of 5% ethanol and 95% gasoline. If his car runs best on a mixture consisting of 10% ethanol and 90% gasoline, how many gallons of ethanol must he add into the gas tank for his car to achieve optimum performance?
a) 9/10
b) 1
c) 10/9
d) 20/19
e) 2
E = 5% of 20 gl = 1 gl
G = 95% of 20 gl = 19
we need to add E. if so, added E = 10% of (19/.9) - 1 = 10/9 gl
C.
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its c. Lets say you add x gallons of ethanol more. Than
(1+x)=(20+x)/10
x=10/9
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Re: Word Problem - chemical mixture [#permalink]
20 Jun 2009, 11:37
It's C.
Using the table:
orig add result
concent 5% 100% 10%
amt 20 x 20+x
= 1 + x = 2 + .10x
= 10/9
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Re: Word Problem - chemical mixture [#permalink]
22 Jun 2009, 10:27
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I also agree it is C. you need to go from 1/20 to (1+x)/(20+x) = 1/10 The trap answer is 1 since 1+1=2/20 =1/10 when it really is 2/21
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Re: Word Problem - chemical mixture [#permalink]
23 Jun 2009, 08:09
Arvindgmat wrote: What do you think is the difficulty level of the question. I did solve it but took a lot of time to find the answer. Took a couple of wrong approaches to solve the problem. i am guessing medium difficulty. Pretty straightforward if someone done the type of question before.
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Re: Word Problem - chemical mixture [#permalink]
23 Jun 2009, 09:47
the solution is simple..
if your try using simple maths its an easy question 500-600 level question , but if you start using logic it becomes relatively a difficult question 600-700 level..
mathematical way: let x litres be added,, so x+1/ 20+x = 1/10 and find x easy as every one else has done here........ but if you start to use logic.. you will end up eating too much time..
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Re: Word Problem - chemical mixture [#permalink]
24 Jun 2009, 12:14
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My vote is for C.
First find the current ratio:
E (ethanol) = 5% x 20 = 1
G (gasoline) = 20 - 1 = 19
Now, set up the new ratio that we are trying to obtain using the current one:
1/9 = (1 + x)/19
19 = 9 + 9x
10 = 9x
x = 10/9
1/9 represents the new ratio we are trying to get of 10% ethanol and 90% gasoline. x is for the amount of gallons we need to add to the current 1 gal. of ethanol to achieve the new 10%.
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Re: Word Problem - chemical mixture [#permalink]
11 Feb 2011, 16:11
Is it that we dont't need to have 20 litres of gasohol? Because if we do, I think the answer will be B. Currently there is 5% of ethanol out of 20 litres of fuel that means the mixture contains 1 litre of ethanol. To have 10% ethanol, Bob needs to have 2 litres of ethanol, therefore he needs to add 1 more litre of ethanol.
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Re: Word Problem - chemical mixture [#permalink]
11 Feb 2011, 16:25
gmatpapa wrote: Bob just filled his car's gas tank with 20 gallons of gasohol, a mixture consisting of 5% ethanol and 95% gasoline. If his car runs best on a mixture consisting of 10% ethanol and 90% gasoline, how many gallons of ethanol must he add into the gas tank for his car to achieve optimum performance?
a) 9/10
b) 1
c) 10/9
d) 20/19
e) 2
Is it that we dont't need to have 20 litres of gasohol? Because if we do, I think the answer will be B.
Currently there is 5% of ethanol out of 20 litres of fuel that means the mixture contains 1 litre of ethanol. To have 10% ethanol, Bob needs to have 2 litres of ethanol, therefore he needs to add 1 more litre of ethanol. Please read the question carefully: "how many gallons of ethanol must he add ..." add not replace. 19 gallons of gasoline which is now in the tank must comprise 90% of the whole fuel after adding some amount of ethanol --> thus whole amount of fuel after adding must be 19/(9/10)=190/9 gallons --> amount of the ethanol which Bob must add is 190/9-20=10/9 gallons. Answer: C.
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Re: Word Problem - chemical mixture [#permalink]
12 Feb 2011, 01:42
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Originally; the fuel contained 20*5/100 = 1 gallon of ethanol After adding x gallons of ethanol; the total weight of the fuel=20+x Amount of ethanol in it will be = 1+x (1+x) is 10% of (20+x) (1+x/20+x)*100=10 100+100x=200+10x 90x=100 x=10/9 Ans: "C"
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Re: Bob just filled his car's gas tank with 20 gallons of [#permalink]
14 Dec 2011, 12:23
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Re: Bob just filled his car's gas tank with 20 gallons of [#permalink]
05 Apr 2012, 06:30
above720 wrote: Bob just filled his car's gas tank with 20 gallons of gasohol, a mixture consisting of 5% ethanol and 95% gasoline. If his car runs best on a mixture consisting of 10% ethanol and 90% gasoline, how many gallons of ethanol must he add into the gas tank for his car to achieve optimum performance?
A. 9/10
B. 1
C. 10/9
D. 20/19
E. 2 It is better to apply formula of weighted average: V1/V2= (C2-C3)/ (C3-C1) V1 and V2=> initial and final volumes of mixture respectively C1= Initial concentation of fluid= 5% C2= Concentration of additive fluid= 100% ethanol in our case C3= Desired concentration of fluid= 10% 20/V2= (100-10)/(10-5) V2= 100/90= 10/9 
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Re: mixture problms [#permalink]
05 Apr 2012, 09:48
TomB wrote: does anybody know some other problems like above problems? I need some extra practice These are standard mixture problems. I have discussed a couple of such problems on my blog: http://www.veritasprep.com/blog/2011/04 ... -mixtures/Also, you should get many such problems under the topic 'mixtures' in any standard GMAT prep book.
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Re: Word Problem - chemical mixture [#permalink]
01 Oct 2012, 00:01
Bunuel wrote: gmatpapa wrote: Bob just filled his car's gas tank with 20 gallons of gasohol, a mixture consisting of 5% ethanol and 95% gasoline. If his car runs best on a mixture consisting of 10% ethanol and 90% gasoline, how many gallons of ethanol must he add into the gas tank for his car to achieve optimum performance?
a) 9/10
b) 1
c) 10/9
d) 20/19
e) 2
Is it that we dont't need to have 20 litres of gasohol? Because if we do, I think the answer will be B.
Currently there is 5% of ethanol out of 20 litres of fuel that means the mixture contains 1 litre of ethanol. To have 10% ethanol, Bob needs to have 2 litres of ethanol, therefore he needs to add 1 more litre of ethanol. Please read the question carefully: "how many gallons of ethanol must he add ..." add not replace. 19 gallons of gasoline which is now in the tank must comprise 90% of the whole fuel after adding some amount of ethanol --> thus whole amount of fuel after adding must be 19/(9/10)=190/9 gallons --> amount of the ethanol which Bob must add is 190/9-20=10/9 gallons. Answer: C. Bunuel, Help me with this. I am clear with this - 19 gallons of gasoline which is now in the tank must comprise 90% of the whole fuel after adding some amount of ethanol --> thus whole amount of fuel after adding must be 19/(9/10)=190/9 gallons Now the total fuel is 190/9 gallons(Gasoline+ethanol). As given in the question ethanol will be 10% of this new solution which is 19/9. What is the mistake here?
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Re: Word Problem - chemical mixture [#permalink]
01 Oct 2012, 08:04
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ENAFEX wrote: Bunuel wrote: gmatpapa wrote: Bob just filled his car's gas tank with 20 gallons of gasohol, a mixture consisting of 5% ethanol and 95% gasoline. If his car runs best on a mixture consisting of 10% ethanol and 90% gasoline, how many gallons of ethanol must he add into the gas tank for his car to achieve optimum performance?
a) 9/10
b) 1
c) 10/9
d) 20/19
e) 2
Is it that we dont't need to have 20 litres of gasohol? Because if we do, I think the answer will be B.
Currently there is 5% of ethanol out of 20 litres of fuel that means the mixture contains 1 litre of ethanol. To have 10% ethanol, Bob needs to have 2 litres of ethanol, therefore he needs to add 1 more litre of ethanol. Please read the question carefully: "how many gallons of ethanol must he add ..." add not replace. 19 gallons of gasoline which is now in the tank must comprise 90% of the whole fuel after adding some amount of ethanol --> thus whole amount of fuel after adding must be 19/(9/10)=190/9 gallons --> amount of the ethanol which Bob must add is 190/9-20=10/9 gallons. Answer: C. Bunuel, Help me with this. I am clear with this - 19 gallons of gasoline which is now in the tank must comprise 90% of the whole fuel after adding some amount of ethanol --> thus whole amount of fuel after adding must be 19/(9/10)=190/9 gallons Now the total fuel is 190/9 gallons(Gasoline+ethanol). As given in the question ethanol will be 10% of this new solution which is 19/9. What is the mistake here? Yes, there will be 19/9 gallons of ethanol in the tank. But we are asked "how many gallons of ethanol must he add ..." and since there were 20*5%=1 gallon of ethanol initially, then we should add 19/9-1=10/9 gallons of ethanol. Hope it's clear.
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Re: Bob just filled his car's gas tank with 20 gallons of [#permalink]
22 Nov 2012, 20:56
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Total -20 gallon gasohol.
95% ethanol and 5%gasoline
which is 19:1
Optimal mixture should be 18:2 as per details given.
Now,
19 gallon of ethanol should be equal to 90%.So for that you should add more than 1 gallon of gasoline.
i.e 19/9/10-20=10/9
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Re: Bob just filled his car's gas tank with 20 gallons of [#permalink]
01 Jan 2013, 14:34
Guys, I made the following formula, could anyone of you please tell me what's wrong with it ?
0.95 (20) + X = 90/100 (20+x)
1+X = 18+0.9x
0.1x = 17 ???
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Re: Bob just filled his car's gas tank with 20 gallons of [#permalink]
01 Jan 2013, 21:51
Emaco wrote: Guys, I made the following formula, could anyone of you please tell me what's wrong with it ?
0.95 (20) + X = 90/100 (20+x)
1+X = 18+0.9x
0.1x = 17 ??? .95 of 20 is the amount of gasoline already in his car. He adds more ethanol and not gasoline so you cannot add x (amount of ethanol added) to .95 of 20. Instead, you need to find the current amount of ethanol and add x to it. .05(20) + x = .10 (20 + x) .9x = 1 x = 10/9
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Re: Bob just filled his car's gas tank with 20 gallons of [#permalink]
02 Jan 2013, 00:11
That's so cool, thanks so much Karishma, it's clear now !
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Re: Bob just filled his car's gas tank with 20 gallons of
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02 Jan 2013, 00:11
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