Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 06 Jul 2015, 23:52

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Borja has just returned from abroad. He has been to Mabaland

Author Message
TAGS:
GMAT Instructor
Joined: 04 Jul 2006
Posts: 1266
Followers: 24

Kudos [?]: 167 [0], given: 0

Borja has just returned from abroad. He has been to Mabaland [#permalink]  07 Aug 2006, 09:19
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Borja has just returned from abroad. He has been to Mabaland and Turaland and still has 1-lira bills from each company. The Mabalian lira is worth $0.05 and the Turish lira is worth$0.23. If Borja's lira bills are worth $12.57 in all, how many possibilities are there for the number of Turish lira bills he has? (A) 7 (B) 8 (C) 9 (D) 10 (E) more than 10 Last edited by kevincan on 07 Aug 2006, 13:17, edited 1 time in total. VP Joined: 29 Dec 2005 Posts: 1348 Followers: 7 Kudos [?]: 37 [0], given: 0 Re: PS: Lira [#permalink] 07 Aug 2006, 13:09 kevincan wrote: Borja has just returned from abroad. He has been to Mabaland and Turaland and still has 1-lira bills from each company. The Mabalian lira is worth$0.05 and the Turish lira is worth $0.23. If Borja's lira bills are worth$12.57 in all, how many possibilities are there for the number of Turish lira bills he has?

(A) 7 (B) 8 (D) 9 (E) 10 (F) more than 10

Mabaland lira = x
Turaland = y

0.5x + 0.23y = 12.57
the LCM of 0.5 and 0.23 is 1.15.

if x = 1, y = 54.43.
if x = 2, y = 54.22
if x = 3, y = 54.00
so every (12.57 - 0.15) - 23(n)x is divisible by y.
there are (12.57-0.15)/1.15 = 12.42/1.15 = 10.8
so total possibilities = 10.8+1 = 11.8

so should be E (or F).

Last edited by Professor on 07 Aug 2006, 18:27, edited 1 time in total.
VP
Joined: 29 Dec 2005
Posts: 1348
Followers: 7

Kudos [?]: 37 [0], given: 0

kevincan wrote:
Correct! Any easier explanations?

i also seek for any better explanation? laxi, are you arround??????
Intern
Joined: 18 Feb 2006
Posts: 23
Followers: 0

Kudos [?]: 1 [0], given: 0

we need the ones digit of the 0.23x to equal 2 or 7, so the value of 0.23x can be displayed as 1.15x - 0.23, as it would start the sequence at 0.92.

1.15x - 0.23 < 12.57
1.15x < 12.8
x < 11.13

so 11 possibilities. (E)
CEO
Joined: 20 Nov 2005
Posts: 2910
Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008
Followers: 19

Kudos [?]: 132 [0], given: 0

E - Total possibilities = 11

5x + 23y = 1257

Only possibilities are when the y is either 4 or 9 because only then last digit of 23y will be 2 or 7.
So all possibilities are 4,14,24,34,44,54 and 9,19,29,39,49.

Because 1257/23 = 54.abcd
So we can't go beyond 54.
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

Similar topics Replies Last post
Similar
Topics:
11 A new tower has just been built at the Verbico military 8 20 Dec 2011, 07:05
35 On the number line above, the segment from 0 to 1 has been 18 03 Nov 2010, 14:45
John has 12 clients and he wants to use color coding to 4 26 Aug 2008, 16:27
Futuristic hates studying for the GMAT. He has decided to 2 08 Sep 2006, 14:49
Alan has a flock of sheep from which he will choose 4 to 4 12 Aug 2006, 13:12
Display posts from previous: Sort by