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Box W and Box V each contain several blue sticks and red

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VP
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Joined: 13 Jun 2004
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Location: London, UK
Schools: Tuck'08
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Box W and Box V each contain several blue sticks and red [#permalink] New post 18 Oct 2004, 18:10
00:00
A
B
C
D
E

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Box W and Box V each contain several blue sticks and red sticks, and all of the red sticks have the same length. The length of each red stick is 18 inches less than the average length of the sticks in Box W and 6 inches greater than the average length of the sticks in Box V. What is the average (arithmetic mean) length, in inches, of the sticks in Box W minus the average length, in inches, of the sticks in Box V?

A. 3
B. 6
C. 12
D. 18
E. 24
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 [#permalink] New post 18 Oct 2004, 19:11
18 + 6 = 24 The difference between avg length of Box w and v
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 [#permalink] New post 18 Oct 2004, 21:16
According to ur question
Length(red)=w(avg) - 18 = v(avg.) + 6

=> w(avg.) - v(avg.) = 18+6 =24
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VP
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Joined: 13 Jun 2004
Posts: 1128
Location: London, UK
Schools: Tuck'08
Followers: 6

Kudos [?]: 21 [0], given: 0

GMAT Tests User
 [#permalink] New post 19 Oct 2004, 00:40
OA is E but I really had difficulties to translate this problem into a correct equation. Thanks.
:done
  [#permalink] 19 Oct 2004, 00:40
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Box W and Box V each contain several blue sticks and red

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