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By what percent is the time taken by 12 men to complete a pa

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By what percent is the time taken by 12 men to complete a pa [#permalink] New post 28 Dec 2012, 04:49
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By what percent is the time taken by 12 men to complete a particular task greater than the time taken by 10 women to complete the same task?

(1) The time taken by 6 men to complete a particular task is 25% more than the time taken by 5 women to complete the same task.

(2) The time taken by 10 men to complete a particular task is 10% less than the time taken by 6 women to complete the same task.

Cheers,
Taz
[Reveal] Spoiler: OA

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Re: By what percent is the time taken by 12 men to complete a pa [#permalink] New post 29 Dec 2012, 11:37
tabsang wrote:
By what percent is the time taken by 12 men to complete a particular task greater than the time taken by 10 women to complete the same task?

(1) The time taken by 6 men to complete a particular task is 25% more than the time taken by 5 women to complete the same task.

(2) The time taken by 10 men to complete a particular task is 10% less than the time taken by 6 women to complete the same task.

Cheers,
Taz


Suppose time taken by each men to finish the work one is m and time taken by each women is w
Rate of each men = 1/m
Rate of each women = 1/w

Rate of 12 men = 12/m => time taken by 12 men to finish the work is m/12
Rate of 10 women = 10/w => time taken by 10 women to finish the work is w/10

we need to find : (time 12men - time 10 women)/(time 10women)
= (m/12 - w/10)/ (w/10)
= (10m - 12w) / 12w = ((5/6)*(m/w)) - 1

STAT1:
The time taken by 6 men to complete a particular task is 25% more than the time taken by 5 women to complete the same task.
time taken by 6men = m/6
time taken by 5women = w/5

m/6 = 1.25 * w/5
=> m/w = 1.25 * 6/5 = 1.5
if we have m/w then we can find ((5/6)*(m/w)) - 1
SO SUFFICIENT!

STAT2:
The time taken by 10 men to complete a particular task is 10% less than the time taken by 6 women to complete the same task.
time taken by 10men = m/10
time taken by 6 women = w/6
m/10 = 0.90 * w/6
=> m/w = 0.90 * 10/6 = 1.5
if we have m/w then we can find ((5/6)*(m/w)) - 1
SO SUFFICIENT!

Hence, Answer will be D.
Hope it helps!
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Re: By what percent is the time taken by 12 men to complete a pa [#permalink] New post 30 Dec 2012, 04:07
tabsang wrote:
By what percent is the time taken by 12 men to complete a particular task greater than the time taken by 10 women to complete the same task?

(1) The time taken by 6 men to complete a particular task is 25% more than the time taken by 5 women to complete the same task.

(2) The time taken by 10 men to complete a particular task is 10% less than the time taken by 6 women to complete the same task.

Cheers,
Taz


To conceptually attack the problem in DS ways, if we have a sense of total work needed by m/w then we can answer the specifics of x m/w

1. 6m = 1.25*5w here work is equal to 5w and m can be expressed in terms of w.
2. 10m = 0.9*6w here too same as in 1 .

So D
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Re: By what percent is the time taken by 12 men to complete a pa [#permalink] New post 15 Sep 2013, 08:37
Is it okay to assume that every man and every owman are working at the same speed.

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Re: By what percent is the time taken by 12 men to complete a pa [#permalink] New post 16 Sep 2013, 01:23
Expert's post
sanjaykvbsingh wrote:
Is it okay to assume that every man and every owman are working at the same speed.

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It would be better if it were mentioned that men and women work at their respective uniform rates, which is clearly assumed there.
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Re: By what percent is the time taken by 12 men to complete a pa [#permalink] New post 21 Oct 2013, 11:14
sanjaykvbsingh wrote:
Is it okay to assume that every man and every owman are working at the same speed.

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Exactly my point.
I chose E on the basis that I couldn't tell whether all men and women worked at the same constant rate. If for example the 6 men work at a rate x, how do I know that the 7th or 8th man added would work at the same uniform rate?

Isn't that a valid concern?
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Re: By what percent is the time taken by 12 men to complete a pa [#permalink] New post 22 Oct 2013, 06:14
6m.... 1.25x
5w....x

so 12m...0.75x
10w.....0.5x

so I is sufficient.

10m...0.9x
6w...x

12m....0.9x (12)/10
10w.....x(10)/6

so II is sufficient.

I could be wrong. I'm still doing the math intuitively rather than logically. I'm going to start proper training from this weekend.
Re: By what percent is the time taken by 12 men to complete a pa   [#permalink] 22 Oct 2013, 06:14
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