tabsang wrote:
By what percent is the time taken by 12 men to complete a particular task greater than the time taken by 10 women to complete the same task?
(1) The time taken by 6 men to complete a particular task is 25% more than the time taken by 5 women to complete the same task.
(2) The time taken by 10 men to complete a particular task is 10% less than the time taken by 6 women to complete the same task.
Cheers,
Taz
Suppose time taken by each men to finish the work one is m and time taken by each women is w
Rate of each men = 1/m
Rate of each women = 1/w
Rate of 12 men = 12/m => time taken by 12 men to finish the work is m/12
Rate of 10 women = 10/w => time taken by 10 women to finish the work is w/10
we need to find : (time 12men - time 10 women)/(time 10women)
= (m/12 - w/10)/ (w/10)
= (10m - 12w) / 12w = ((5/6)*(m/w)) - 1
STAT1:
The time taken by 6 men to complete a particular task is 25% more than the time taken by 5 women to complete the same task.
time taken by 6men = m/6
time taken by 5women = w/5
m/6 = 1.25 * w/5
=> m/w = 1.25 * 6/5 = 1.5
if we have m/w then we can find ((5/6)*(m/w)) - 1
SO SUFFICIENT!
STAT2:
The time taken by 10 men to complete a particular task is 10% less than the time taken by 6 women to complete the same task.
time taken by 10men = m/10
time taken by 6 women = w/6
m/10 = 0.90 * w/6
=> m/w = 0.90 * 10/6 = 1.5
if we have m/w then we can find ((5/6)*(m/w)) - 1
SO SUFFICIENT!
Hence, Answer will be D.
Hope it helps!
_________________
ankit
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