tabsang wrote:

By what percent is the time taken by 12 men to complete a particular task greater than the time taken by 10 women to complete the same task?

(1) The time taken by 6 men to complete a particular task is 25% more than the time taken by 5 women to complete the same task.

(2) The time taken by 10 men to complete a particular task is 10% less than the time taken by 6 women to complete the same task.

Cheers,

Taz

Suppose time taken by each men to finish the work one is m and time taken by each women is w

Rate of each men = 1/m

Rate of each women = 1/w

Rate of 12 men = 12/m => time taken by 12 men to finish the work is m/12

Rate of 10 women = 10/w => time taken by 10 women to finish the work is w/10

we need to find : (time 12men - time 10 women)/(time 10women)

= (m/12 - w/10)/ (w/10)

= (10m - 12w) / 12w = ((5/6)*(m/w)) - 1

STAT1:

The time taken by 6 men to complete a particular task is 25% more than the time taken by 5 women to complete the same task.

time taken by 6men = m/6

time taken by 5women = w/5

m/6 = 1.25 * w/5

=> m/w = 1.25 * 6/5 = 1.5

if we have m/w then we can find ((5/6)*(m/w)) - 1

SO SUFFICIENT!

STAT2:

The time taken by 10 men to complete a particular task is 10% less than the time taken by 6 women to complete the same task.

time taken by 10men = m/10

time taken by 6 women = w/6

m/10 = 0.90 * w/6

=> m/w = 0.90 * 10/6 = 1.5

if we have m/w then we can find ((5/6)*(m/w)) - 1

SO SUFFICIENT!

Hence, Answer will be D.

Hope it helps!

_________________

Ankit

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