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# Can A and can В are both right circular cylinders. The radiu

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Can A and can В are both right circular cylinders. The radiu [#permalink]  17 Mar 2011, 13:46
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64% (01:57) correct 35% (00:52) wrong based on 39 sessions
Can A and can В are both right circular cylinders. The radius of can A is twice the radius of can B, while the height of can A is half the height of can B. If it costs $4.00 to fill half of can B with a certain brand of gasoline, how much would it cost to completely fill can A with the same brand of gasoline? (A)$1
(B) $2 (C)$4
(D) $8 (E)$16
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Re: 2. (KP) Can A and can В are both right circular cylinders. T [#permalink]  17 Mar 2011, 14:09
banksy wrote:
2. (KP) Can A and can В are both right circular cylinders. The radius of can A is twice the radius of can B, while the height of can A is half the height of can B. If it costs $4.00 to fill half of can B with a certain brand of gasoline, how much would it cost to completely fill can A with the same brand of gasoline? (A)$1
(B) $2 (C)$4
(D) $8 (E)$16

Let x be the radius of b and 2h be the height of B. Therefore, radius of A = 2x and height = h

Vol of b = 3.14*x^2*2h
Vol of a = 3.14*4x^2*h

cost to fill half of B = $4 --> cost to fill full B =$8
--> 3.14*x^2*2h = 8 --> 3.14*x^2*h = 4 --> 4*(3.14*x^2*h) = $16 Ans E SVP Joined: 16 Nov 2010 Posts: 1693 Location: United States (IN) Concentration: Strategy, Technology Followers: 26 Kudos [?]: 252 [0], given: 35 Re: 2. (KP) Can A and can В are both right circular cylinders. T [#permalink] 19 Mar 2011, 00:57 B -> pi * r^2*h A -> pi * 4r^2 * h/2 = 2 * pi * r^2 * h So, Vol of 1/2 of can B = vol of 1/4 can A So can A will take 4 * 4 =$16 for gasoline.
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Re: 2. (KP) Can A and can В are both right circular cylinders. T [#permalink]  19 Mar 2011, 01:52
banksy wrote:
2. (KP) Can A and can В are both right circular cylinders. The radius of can A is twice the radius of can B, while the height of can A is half the height of can B. If it costs $4.00 to fill half of can B with a certain brand of gasoline, how much would it cost to completely fill can A with the same brand of gasoline? (A)$1
(B) $2 (C)$4
(D) $8 (E)$16

Let radius of B be r and A be 2r
vol of B=πr^2h
vol of a=4πr^2h (radius= (2r)) == twice the volume of B

To fill 1/2 of B it cost 4$to fill B it cost 8$
to fill 2b ie (a) it cost 16$Director Status: GMAT Learner Joined: 14 Jul 2010 Posts: 657 Followers: 27 Kudos [?]: 141 [0], given: 31 Re: 2. (KP) Can A and can В are both right circular cylinders. T [#permalink] 19 Mar 2011, 02:05 banksy wrote: 2. (KP) Can A and can В are both right circular cylinders. The radius of can A is twice the radius of can B, while the height of can A is half the height of can B. If it costs$4.00 to fill half of can B with a certain brand of gasoline, how much would it cost to completely fill can A with the same brand of gasoline?
(A) $1 (B)$2
(C) $4 (D)$8
(E) $16 Volume of right circular cylinder = 2πr^2h Let Radius of Can A= 4 Height of can A = 2 Volume of Can A = 2*π*r^2*h = 2*π*4^2*2 = 64π Radius of can B = 2 Height of can B = 4 Volume of Can B= 2*π*r^2*h = 2*π*2^2*4 = 32π 1/2 of B= 32π/2=16π thus cost required to fill can A = (4/16π)*64π=$16
Ans E.
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Re: 2. (KP) Can A and can В are both right circular cylinders. T [#permalink]  22 Sep 2013, 19:34
sorry guys the answer is $8. lets consider the radius of can A to be 2x. radius of can B to be x. let the height of can A be y. Let the height of can B be 2y. Volume of a can A (pie 4x^2y) Volume of can B (pie 2 x^2 y). Since volume of can B is exactly half of can A. It costs$8 to fill can A completely.
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Re: 2. (KP) Can A and can В are both right circular cylinders. T [#permalink]  22 Sep 2013, 23:26
Expert's post
mohnish104 wrote:
sorry guys the answer is $8. lets consider the radius of can A to be 2x. radius of can B to be x. let the height of can A be y. Let the height of can B be 2y. Volume of a can A (pie 4x^2y) Volume of can B (pie 2 x^2 y). Since volume of can B is exactly half of can A. It costs$8 to fill can A completely.

Notice that we a re told that it costs $4.00 to fill half of can B. so the correct answer is E, not D. Can A and can В are both right circular cylinders. The radius of can A is twice the radius of can B, while the height of can A is half the height of can B. If it costs$4.00 to fill half of can B with a certain brand of gasoline, how much would it cost to completely fill can A with the same brand of gasoline?

(A) $1 (B)$2
(C) $4 (D)$8
(E) $16 Volume of B = \pi{r^2}h Volume of A = \pi{(2r)^2}(\frac{h}{2})=2\pi{r^2}h. Thus the volume of can A is twice the volume of cam B. If it costs$4.00 to fill half of can B, then it costs 4*$4=$16 to completely fill can A.

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Re: Can A and can В are both right circular cylinders. The radiu [#permalink]  23 Sep 2013, 04:25
Thank you Bunuel. I guess the answer has been wrongly pointed out in the Kaplan tests.
Re: Can A and can В are both right circular cylinders. The radiu   [#permalink] 23 Sep 2013, 04:25
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