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Can anyone define the operator for the square? I tried

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Can anyone define the operator for the square? I tried [#permalink] New post 18 Aug 2003, 13:06
Can anyone define the operator for the square?
I tried addition, subtraction, division, and multiplication, and I could not get the result.
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mis [#permalink] New post 18 Aug 2003, 14:06
You have misinterpreted the problem. This type of problem "invents" a new operator, defined in the question stem. Follow the patten that it shows you to get the answer.
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 [#permalink] New post 18 Aug 2003, 15:28
A=4, B=2... answer: A
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 [#permalink] New post 19 Aug 2003, 07:03
Well done to all of you.

Just in case for those who still could not catch it, and I have just figured it.

Column A

Try to substitute x=0, and y=2 into the equation.

Column B

Try to substitute x = -1, and y = -1 into the equation.
  [#permalink] 19 Aug 2003, 07:03
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Can anyone define the operator for the square? I tried

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