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Can anyone show the steps to find both the ways to

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Can anyone show the steps to find both the ways to [#permalink] New post 18 Aug 2003, 13:00
Can anyone show the steps to find both the ways to distribute total no. of bills is equal to the ways if at least one person get $3.
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 [#permalink] New post 18 Aug 2003, 16:00
lets calculate A:
7=1+1+5=1+2+4=1+3+3=2+2+3=> there are 4*3! such ways
lets calculate B:
7=7+0+0=6+1+0=5+2+0=5+1+1=4+3+0 (so on) => there are 10*3! such ways

B>A
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 [#permalink] New post 19 Aug 2003, 06:58
Column A = Column B.

The answer given is not quite correct.
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 [#permalink] New post 19 Aug 2003, 10:02
then i must have misunderstood B... ive calculated the number of ways of distributing 7 bills, but without considering the condition "each one receives 1 bill"... my bad, sorry... taking that into consideration, A=B
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 [#permalink] New post 23 Aug 2003, 04:25
Can anyone confirm my answer?

Column A

3+3+1
3+2+2
3+1+3


Column B

1+3+3
1+2+4
1+1+5
  [#permalink] 23 Aug 2003, 04:25
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