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Can anyone tell me the fastest approach to such questions

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Can anyone tell me the fastest approach to such questions [#permalink]

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New post 29 Oct 2007, 21:17
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A
B
C
D
E

Difficulty:

(N/A)

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0% (00:00) correct 0% (00:00) wrong based on 0 sessions

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Can anyone tell me the fastest approach to such questions
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Re: PS: Set 27 Q 8 [#permalink]

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New post 29 Oct 2007, 21:23
I would say E.
39/128 = 39/2^7.

the divisor is a power of 2, so it should end at terminating decimal.
Re: PS: Set 27 Q 8   [#permalink] 29 Oct 2007, 21:23
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