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Can anyone tell me the fastest approach to such questions

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Can anyone tell me the fastest approach to such questions [#permalink] New post 29 Oct 2007, 22:17
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Can anyone tell me the fastest approach to such questions
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Re: PS: Set 27 Q 8 [#permalink] New post 29 Oct 2007, 22:23
I would say E.
39/128 = 39/2^7.

the divisor is a power of 2, so it should end at terminating decimal.
Re: PS: Set 27 Q 8   [#permalink] 29 Oct 2007, 22:23
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