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can some one answer this question for me please

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can some one answer this question for me please [#permalink] New post 02 Jan 2011, 20:21
The owner of a hobby store needed to calculate the percentage of customers who purchase wood glue. Upon completing his survey, he noticed that 60% of the people that entered his store purchased an item. Of those customers, 15 percent purchased wood glue. What percent of the people that entered the store purchased wood glue? answer is 9%

I dont know what I am doing wrong, I cant get the answer

Also this one,
Frank is 15 years younger then John. In 5 years John will be twice as old as Frank. How old will Frank be in four years? answer is 14
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Re: can some one answer this question for me please [#permalink] New post 02 Jan 2011, 20:39
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Welcome to GMAT Club!

Let X be the number of people that entered his store, then:

60% of X = 0.6*X - the number of people who purchased an item.

15% of 0.6*X = 0.15*0.6*X = 0.09*X = 9/100 X = 9% of X - the number of people who purchased wood glue.

Please, post one question per topic.
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Re: can some one answer this question for me please [#permalink] New post 02 Jan 2011, 20:59
Franks age= x
Johns age = x+15

After 5 years

Franks age = x+5
Johns age = x+15 +5 = x+20

Given x+20 = 2(x+5) ==> x=10

So x , which we had assumed as present age = 10
Fours years later = 10+4 = 14 years ....ans
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Re: can some one answer this question for me please [#permalink] New post 03 Jan 2011, 02:27
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rdhookar wrote:
The owner of a hobby store needed to calculate the percentage of customers who purchase wood glue. Upon completing his survey, he noticed that 60% of the people that entered his store purchased an item. Of those customers, 15 percent purchased wood glue. What percent of the people that entered the store purchased wood glue? answer is 9%

I dont know what I am doing wrong, I cant get the answer

Also this one,
Frank is 15 years younger then John. In 5 years John will be twice as old as Frank. How old will Frank be in four years? answer is 14


Welcome to GMAT Club!

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Re: can some one answer this question for me please   [#permalink] 03 Jan 2011, 02:27
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