Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 02 Jul 2015, 15:31

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

Can some one explain this solution in detail

Author Message
TAGS:
Manager
Joined: 21 Jun 2004
Posts: 52
Followers: 1

Kudos [?]: 1 [0], given: 0

Can some one explain this solution in detail [#permalink]  12 Jul 2004, 22:35
CAN SOME ONE EXPLAIN ME THIS SOLUTION

Find area if a line goes through x's greater than or equal 2, y's greater than or equal 3, and y's less than or equal to 9-x.

The area is that of a triangle with points (2,3) (2,7) (6,3)
height and base of triangle is 4 and represents a isoceles right triangle
area is 4*4/2 = 8

Paul
Senior Manager
Joined: 25 Dec 2003
Posts: 360
Location: India
Followers: 1

Kudos [?]: 17 [0], given: 0

Find area if a line goes through x's greater than or equal 2, y's greater than or equal 3, and y's less than or equal to 9-x.

Solution -

Plot the points .. (the key to this question is to find three points to make the triangle).

We know X is minimum 2
Y is minimum 3

so we get one point as (2,3) and Use these 2 co-ordinates (x=2 , y=3) in the equation y=9-x.

For x =2, Y=7
For y=3, x=6

Now we have 3 points to make a triangle. (2,3), (2,7) and (6,3). From this we know that the the lenghts of 2 sides are 4. This makes it isocls triangle. Are is bh/2. 4x4/2 = 8.

I hope this helped.
_________________

Giving another SHOT

Manager
Joined: 07 May 2004
Posts: 183
Location: Ukraine, Russia(part-time)
Followers: 2

Kudos [?]: 9 [0], given: 0

Re: Can some one explain this solution in detail [#permalink]  14 Jul 2004, 06:57
K_s_r wrote:
CAN SOME ONE EXPLAIN ME THIS SOLUTION

Find area if a line goes through x's greater than or equal 2, y's greater than or equal 3, and y's less than or equal to 9-x.

The area is that of a triangle with points (2,3) (2,7) (6,3)
height and base of triangle is 4 and represents a isoceles right triangle
area is 4*4/2 = 8

Paul

There are 3 points of intersection for these 3 lines (X>=2, Y >= 3, Y <= 9-X), their coords were listed by Paul. Then we note that the triangle, formed by these 3 points is right and calculate its area by multiplying 2 sides which form right angle and dividing the result by 2.

4*4/2 = 8 is the answer.
Manager
Joined: 21 Jun 2004
Posts: 52
Followers: 1

Kudos [?]: 1 [0], given: 0

Thank you both of you. That was really helpful.

I just went on subsituting the X value and got Y values, never tried the other direction.
Senior Manager
Joined: 07 Oct 2003
Posts: 358
Location: Manhattan
Followers: 2

Kudos [?]: 9 [0], given: 0

I'm in trouble on this one.
picked 3 points accordingly:
(2,3), (3,6), (6,3)
from this, base of the triangle is equal to 4, and height is equal to 3
1/2*3*4=6, not 8!!

What am I doing wrong?
Manager
Joined: 21 Jun 2004
Posts: 52
Followers: 1

Kudos [?]: 1 [0], given: 0

lastochka wrote:
I'm in trouble on this one.
picked 3 points accordingly:
(2,3), (3,6), (6,3)
from this, base of the triangle is equal to 4, and height is equal to 3
1/2*3*4=6, not 8!!

What am I doing wrong?

I guess the problem is here

u took the numbers (2,3) and did not derive the next points from these two numbers, you just pulled out x = 3 and got the points (3,6) & (6,3)

That may not really satisfy the conditions

But I also have problem with the follwing poitns

take (x,y) = (3,4) then 2nd poitn becomes x,y = 3,6 & 3rd is x,y = 5,4

Hmmmmmmmm,

Good poitn some one explain,
Similar topics Replies Last post
Similar
Topics:
Can some one please explain this to me 1 15 Jun 2008, 11:45
This one is confusing. Need some detailed explaination. 4 11 Jun 2008, 10:01
4 Detailed solution will be appreciated. Thanks 4 10 Jun 2008, 03:40
8 Detailed solution will be appreciated. Thanks 8 10 Jun 2008, 03:39
Detailed solution will be appreciated. Thanks 3 10 Jun 2008, 03:38
Display posts from previous: Sort by