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Manager
Joined: 20 May 2006
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Can someone do the math on this step by step: What is the [#permalink]
30 Sep 2006, 20:15
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Can someone do the math on this step by step:
What is the remainder when positive integer x is divided by 6?
1) When x is divided by 2, the remainder is 1, and when x is divided by 3, the remainder is 0.
2) When x is divided by 12, the remainder is 3
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Intern
Joined: 04 Sep 2006
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D
1) When x is divided by 2, the remainder is 1, and when x is divided by 3, the remainder is 0.
First part says number is odd and second says it is multiple of three. So values may be 3,9,15,21,27
So it will always have constant remainder of 3 when divided by 6.
2) When x is divided by 12, the remainder is 3
It means 12m+3 i.e 6(2k)+3 i.e 6n+3 hence constant remainder.
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SVP
Joined: 05 Jul 2006
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What is the remainder when positive integer x is divided by 6?
1) When x is divided by 2, the remainder is 1, and when x is divided by 3, the remainder is 0.
2) When x is divided by 12, the remainder is 3
FROM ONE
X = 2Q+1 X COULD BE 1,3,5,7,9,11,13,15,17,19,21
X IS DIVISIBLE BY THREE 9,15,3, WHEN DEVIDED BY 6 REMAINDER IS ALWAYS THREE .....SUFF
FROM TWO
X= 12Q+3 X COULD BE 3,15,27.....REMAINDER IS ALWAYS THREE..SUFF
MY ANSWER IS D
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Director
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Both A and B are seperately sufficent to answer .
Answer is D
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