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Can someone do the math on this step by step: What is the

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New post 30 Sep 2006, 20:15
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Can someone do the math on this step by step:

What is the remainder when positive integer x is divided by 6?

1) When x is divided by 2, the remainder is 1, and when x is divided by 3, the remainder is 0.

2) When x is divided by 12, the remainder is 3
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New post 01 Oct 2006, 01:28
D

1) When x is divided by 2, the remainder is 1, and when x is divided by 3, the remainder is 0.

First part says number is odd and second says it is multiple of three. So values may be 3,9,15,21,27

So it will always have constant remainder of 3 when divided by 6.

2) When x is divided by 12, the remainder is 3

It means 12m+3 i.e 6(2k)+3 i.e 6n+3 hence constant remainder.
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New post 01 Oct 2006, 09:34
What is the remainder when positive integer x is divided by 6?

1) When x is divided by 2, the remainder is 1, and when x is divided by 3, the remainder is 0.

2) When x is divided by 12, the remainder is 3

FROM ONE

X = 2Q+1 X COULD BE 1,3,5,7,9,11,13,15,17,19,21
X IS DIVISIBLE BY THREE 9,15,3, WHEN DEVIDED BY 6 REMAINDER IS ALWAYS THREE .....SUFF

FROM TWO

X= 12Q+3 X COULD BE 3,15,27.....REMAINDER IS ALWAYS THREE..SUFF

MY ANSWER IS D
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New post 02 Oct 2006, 10:43
Both A and B are seperately sufficent to answer .

Answer is D
  [#permalink] 02 Oct 2006, 10:43
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