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Can you do this in 1 min? Is 2^x>75 ? 1) 3^x >50 2)

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Can you do this in 1 min? Is 2^x>75 ? 1) 3^x >50 2) [#permalink] New post 16 Sep 2003, 00:48
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Can you do this in 1 min?

Is 2^x>75 ?

1) 3^x >50
2) 2^x * 3^x > 1500
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 [#permalink] New post 16 Sep 2003, 20:54
I think answer is E

If 2^x>75 then x>=7 since 2^6=64

In B: 2^x+3^x>1500

If x=6: 2^6=64 and 3^6=729 64*729 but 2^6<75
If x=7 2^7+3^7 must be >1500 and 2^7>75

Then is not sufficient

Combined:

If B=50 (its almost the same as trying with 51 and much easier to calculate)

2^x > 30 not suff.
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 [#permalink] New post 16 Sep 2003, 21:14
MartinMag wrote:
I think answer is E

If 2^x>75 then x>=7 since 2^6=64

In B: 2^x+3^x>1500

If x=6: 2^6=64 and 3^6=729 64*729 but 2^6<75
If x=7 2^7+3^7 must be >1500 and 2^7>75

Then is not sufficient

Combined:

If B=50 (its almost the same as trying with 51 and much easier to calculate)

2^x > 30 not suff.


Agree. It has to be E.

Martin, Good job. The only thing I disagree with your solution is that it was never said that x was an integer in the question stem. So, we can say x starts at a value between 6 and 7.

Last edited by edealfan on 16 Sep 2003, 21:20, edited 1 time in total.
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 [#permalink] New post 16 Sep 2003, 21:17
True. I missed that.

Doesn't change the answer though
  [#permalink] 16 Sep 2003, 21:17
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