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# Can you tell me the solution of this one

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Senior Manager
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Can you tell me the solution of this one [#permalink]

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22 Jul 2006, 16:46
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Can you tell me the solution of this one ?
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Director
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22 Jul 2006, 18:23
I get B

for the 1st case:

time taken = y/x + (40-y)/1.25x = (40+0.25y)/1.25x

for the second case:-

time taken = 40/x

To find the ratios between time taken, divide one time by the other. The x terms cancel out and we get an expression in terms of y.
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23 Jul 2006, 00:14
Yup B is correct..

I messed up the equation at some point and got an equation with both x & y in it.
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26 Jul 2006, 04:17
B

Time taken when travelling at different speeds = y/x + 40-y/1.5x
= 0.5y + 40/1.5x

Time taken when travelling at constant speed = 40/x

Percent = (0.5y +40/1.5x)*100/40/x
= (0.5y + 40)/ 60

hence only y is required.

Hence B is suff
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