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Challenge - Radical Exponents (m06q20)

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Re: Challenge - Radical Exponents (m06q20) [#permalink] New post 01 Jun 2011, 06:25
toughmat wrote:
I get the following results.Image


^^ what you did so far is correct. Further to match with the given choices, split 5^2*\sqrt{^2} as (5^2)\sqrt{^2} = (25)\sqrt{^2}, which is given in choices
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Re: Challenge - Radical Exponents (m06q20) [#permalink] New post 10 Jun 2011, 03:18
(a^x)^m = (a^m)^x
(5^[square_root]2)^2 = (5^2)^[square_root]2 = 25^[square_root]2
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Re: Challenge - Radical Exponents (m06q20) [#permalink] New post 10 Jun 2011, 03:19
hi, i was struggling to write ' to the power ' in symbols.
can somebody guide me please.
thanks
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Re: Challenge - Radical Exponents (m06q20) [#permalink] New post 04 Jun 2012, 21:36
Answer : 25^sqrt{2}
(5^sqrt{2})^2 = 5^ sqrt{2} * 5^ sqrt{2}
= 5^ sqrt{2}
= 25^ sqrt{2}
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Re: Challenge - Radical Exponents (m06q20) [#permalink] New post 05 Jun 2012, 03:16
B is the answer. Tricky one but remember that the exponents will multiply each other, giving you 5^(2root2).

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Re: Challenge - Radical Exponents (m06q20) [#permalink] New post 13 Sep 2012, 07:35
a^b^c is a^(b^c) and not a^bc.So ,root(2)^2=1.9946~2;5^2=25
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Re: Challenge - Radical Exponents (m06q20) [#permalink] New post 04 Jun 2013, 05:18
Expert's post
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Re: Challenge - Radical Exponents (m06q20) [#permalink] New post 04 Jun 2013, 07:48
The answer is B. (5^sqrt{2})^2 = (5^2)^sqrt{2} = 25^sqrt{2} :)
Re: Challenge - Radical Exponents (m06q20)   [#permalink] 04 Jun 2013, 07:48
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