Challenge - Radical Exponents (m06q20) : Retired Discussions [Locked] - Page 2
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# Challenge - Radical Exponents (m06q20)

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Intern
Joined: 24 May 2010
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01 Jun 2011, 06:25
toughmat wrote:
I get the following results.

^^ what you did so far is correct. Further to match with the given choices, split $$5^2*\sqrt{^2}$$ as $$(5^2)\sqrt{^2} = (25)\sqrt{^2}$$, which is given in choices
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10 Jun 2011, 03:18
(a^x)^m = (a^m)^x
(5^[square_root]2)^2 = (5^2)^[square_root]2 = 25^[square_root]2
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10 Jun 2011, 03:19
hi, i was struggling to write ' to the power ' in symbols.
thanks
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04 Jun 2012, 21:36
(5^sqrt{2})^2 = 5^ sqrt{2} * 5^ sqrt{2}
= 5^ sqrt{2}
= 25^ sqrt{2}
Senior Manager
Joined: 15 Sep 2009
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05 Jun 2012, 03:16
B is the answer. Tricky one but remember that the exponents will multiply each other, giving you 5^(2root2).

Cheers.
_________________

+1 Kudos me - I'm half Irish, half Prussian.

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13 Sep 2012, 07:35
a^b^c is a^(b^c) and not a^bc.So ,root(2)^2=1.9946~2;5^2=25
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04 Jun 2013, 05:18
The square of $$5^{\sqrt{2}}$$ = ?

A. $$5^2$$
B. $$25^{\sqrt{2}}$$
C. $$25$$
D. $$25^{2\sqrt{2}}$$
E. $$5^{\sqrt{2}^2}$$

$$(5^{\sqrt{2}})^2=5^{2*\sqrt{2}}=(5^2)^{\sqrt{2}}=25^{\sqrt{2}}$$.

_________________
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04 Jun 2013, 07:48
The answer is B. (5^sqrt{2})^2 = (5^2)^sqrt{2} = 25^sqrt{2}

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# Challenge - Radical Exponents (m06q20)

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