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# Circle C is in the xy-plane, what is the area of the circle?

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Circle C is in the xy-plane, what is the area of the circle? [#permalink]  25 Aug 2010, 03:46
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Circle C is in the xy-plane, what is the area of the circle?

(1) Points (-2, 0) and (0,2) lie on the circle.
(2) The radius of the circle is equal to or less than 2^(1/2).
[Reveal] Spoiler: OA
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Re: DS-Circle [#permalink]  25 Aug 2010, 04:29
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jitendra wrote:
Circle C is in the xy-plane, what is the area of the circle?

(1) Points (-2, 0) and (0,2) lie on the circle.
(2) The radius of the circle is equal to or less than 2^(1/2).

$$area=\pi{r^2}$$, so we should find the value of radius.

It would be better if you visualize this problem.

(1) Points (-2, 0) and (0,2) lie on the circle --> two points DO NOT define a circle (three points does), hence we can have numerous circles containing these two points, thus we can not find single numerical value of radius. Not sufficient.

Side note: if you put points (-2, 0) and (0,2) on XY-plane you can see that center of the circle must be on the line $$y=-x$$ (the center of the circle must be equidistant from two pints given).

(2) The radius of the circle is equal to or less than $$\sqrt{2}$$ --> $$r\leq{\sqrt{2}}$$. Clearly insufficient.

(1)+(2) The distance between the 2 points given is $$d=\sqrt{2^2+2^2}=2\sqrt{2}$$, so it's min length of diameter of the circle passing these points (diameter of a circle passing 2 points can not be less than the distance between these 2 points), thus half of $$2\sqrt{2}$$ is min length of the radius of the circle --> $$r\geq{\sqrt{2}}$$ but as from (2) $$r\leq{\sqrt{2}}$$ then $$r=\sqrt{2}$$ --> $$area=\pi{r^2}=2\pi$$. Sufficient.

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Re: DS-Circle [#permalink]  25 Aug 2010, 09:03
Good question...As Bunuel said its easier to visualise this and solve than just solving on paper!
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Re: DS-Circle [#permalink]  05 May 2011, 21:44
a+b

distance = 2* 2^(1/2) and r <= 2^(1/2)

if r = 1, then diameter = 2 which is less than 2 * 2^(1/2).Not possible.
means r = 2^(1/2).

thus area = pi * [2^(1/2)]^2.

Hence C
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Re: Circle C is in the xy-plane, what is the area of the circle? [#permalink]  27 Jun 2013, 21:30
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Bumping for review and further discussion*. Get a kudos point for an alternative solution!

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Re: Circle C is in the xy-plane, what is the area of the circle? [#permalink]  28 Jun 2013, 21:46
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Adding to Bunnel's explanation, another way to arrive at why r >=\sqrt{2} is because the sum of any two sides of a triangle is greater than or equal to the third side. The triangle under consideration would be the one formed by the points (-2,0) , (0,2) and the center of the circle. Two sides of this triangle are equal to the radii of the circle. Thus, r+r >= distance between points (-2,0) , (0,2) = 2 \sqrt{2}.
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Re: DS-Circle [#permalink]  06 Feb 2014, 19:51
Bunuel wrote:
jitendra wrote:

Side note: if you put points (-2, 0) and (0,2) on XY-plane you can see that center of the circle must be on the line $$y=-x$$ (the center of the circle must be equidistant from two pints given).

Can you please elaborate on this point.
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Re: Circle C is in the xy-plane, what is the area of the circle? [#permalink]  08 Mar 2015, 04:52
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: Circle C is in the xy-plane, what is the area of the circle?   [#permalink] 08 Mar 2015, 04:52
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