Circle O is inscribed within square ABCD. Square EFGH is inscribed within circle O. What is ratio of the area ABCD to the area of EFGH?
Again i am dumb in math so please explain me the answer.I will appreciate your help guys. Thanks-------------
length of a side of square ABCD = x (suppose 10) = hypoteneous of square EFGH
side of the square EFGH = s
hypoteneous of square EFGH = sqrt (2s^2)
x^2 = sqrt (2s^2)
10^2 = sqrt (2s^2)
2s^2 = 100
s^2 = 50 = 5 sqrt(2)
area of square ABCD = 10x10= 100
area of square EFGH = (5sqrt(2))^2 = 50
area of square ABCD: area of square EFGH = 100:50 or 2:1.