thts the OA... but can you pls elaborate on the conclusion that u drew form the st 1...
Statement 1: Arc AB = 120.
Theorem: The angle subtended by the arc to any point on the circumference of the circle of which it is a part. This angle is always half the central angle. Thus angle AEB = 60. You can refer to this link for more information: http://www.mathopenref.com/arc.html
Furthermore, the angle EFB = 90. Therefore triangle AEB is an equilateral triangle. Hope that helps.