circle properties handy to solve ths?

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circle properties handy to solve ths? [#permalink]

07 Sep 2009, 10:14

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Hi,

i m not too convinced with the OA... can i have answers with explanations? thanks

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Re: circle properties handy to solve ths? [#permalink]

07 Sep 2009, 10:34

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Re: circle properties handy to solve ths? [#permalink]

07 Sep 2009, 10:36

meenal8284 wrote:

Hi,

i m not too convinced with the OA... can i have answers with explanations? thanks

What is the question?

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Re: circle properties handy to solve ths? [#permalink]

07 Sep 2009, 11:57

meenal8284 wrote:

Hi,

i m not too convinced with the OA... can i have answers with explanations? thanks

Where is the -1 option for kudos ??? :lol:

hehe, just kidding.
Plz post your question.

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Re: circle properties handy to solve ths? [#permalink]

07 Sep 2009, 13:31

looks like the file isnt getting uploaded...
pls find one of the questions attached.
thanks

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DS- Circle properties.JPG [ 33.46 KiB | Viewed 655 times ]

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Re: circle properties handy to solve ths? [#permalink]

07 Sep 2009, 13:39

Answer is C

1) Arc AB = 120, so angle AEB = 60
Thus triangle AEB is an equilateral triangle, but we do not know the measure of any side - Not sufficient
2) Segment AB = 2 - Not sufficient

Together sufficient to calculate the perimeter of triangle AEB

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Re: circle properties handy to solve ths? [#permalink]

07 Sep 2009, 15:06

thts the OA... but can you pls elaborate on the conclusion that u drew form the st 1...

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Re: circle properties handy to solve ths? [#permalink]

07 Sep 2009, 15:27

meenal8284 wrote:

thts the OA... but can you pls elaborate on the conclusion that u drew form the st 1...

Statement 1: Arc AB = 120.
Theorem: The angle subtended by the arc to any point on the circumference of the circle of which it is a part. This angle is always half the central angle. Thus angle AEB = 60. You can refer to this link for more information: http://www.mathopenref.com/arc.html
Furthermore, the angle EFB = 90. Therefore triangle AEB is an equilateral triangle. Hope that helps.

Re: circle properties handy to solve ths? [#permalink] 07 Sep 2009, 15:27

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circle properties handy to solve ths?

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circle properties handy to solve ths?

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