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Circles inside a circle [#permalink] New post 07 Oct 2009, 16:27
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Three circles of radius 1 are externally tangent to each other and internally
tangent to a larger circle. What is the radius of the larger circle?
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Re: Circles inside a circle [#permalink] New post 07 Oct 2009, 16:39
Answer is D:

The centers of smaller internal circles create an equilateral triangle, with side S = 2.
Intersection point of medians of this triangle lie on the origin/center of the larger circle.
So the radius of the big circle = 2/3*(length of median) + (radius of the smaller circle).
R = 2/3*(\sqrt{3}/2)*S + 1 = (2/\sqrt{3}) + 1 = (3 + 2\sqrt{3})/3
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Re: Circles inside a circle [#permalink] New post 08 Oct 2009, 09:28
I don't have an OA, but I'm getting D too.

I put an equilateral triangle with a side of 2 with vertices in the centers of the small circles. The circumcircle of an equilateral triangle is \frac{S}{\sqrt{3}}, so the distance between the vertices and the center of the large circle is \frac{2}{\sqrt{3}}. Now add the distance between the vertices to the large circle, which is 1.
\frac{2}{\sqrt{3}}+1
Which is equal to D.
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Re: Circles inside a circle [#permalink] New post 12 Oct 2009, 01:19
hi, agree, i got D as well
Re: Circles inside a circle   [#permalink] 12 Oct 2009, 01:19
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