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Club # of Students Chess 40 Drama 30 Math 25 The table [#permalink]
07 Jan 2008, 18:35

00:00

A

B

C

D

E

Difficulty:

(N/A)

Question Stats:

50% (04:31) correct
50% (01:15) wrong based on 9 sessions

Club # of Students Chess 40 Drama 30 Math 25

The table above shows the number of students in three clubs at McAuliffe School. Although no student is in all three clubs, 10 students are in both Chess and Drama, 5 students are in both Chess and Math, and 6 students are in both Drama and Math. How Many different students are in the three clubs?

68 69 74 79 84

This problem can be solved by setting up a venn diagram. However, I was wondering how you could solve by setting up an equation (if that's even possible).

Re: OG PS #179 - Students question [#permalink]
07 Jan 2008, 18:52

74 is the answer. Use the equation, n(atleast one)= N(A)+N(B)+N(C)-N(exactly two)- 2N(ALL THREE) total diff students= 40+30+25-10-5-6= 74 ( we are given no tudent attens all three)

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