Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Club X has more than 10 but fewer than 40 members. Sometimes [#permalink]

Show Tags

12 Dec 2012, 06:31

2

This post received KUDOS

38

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

55% (hard)

Question Stats:

67% (03:41) correct
33% (02:11) wrong based on 1114 sessions

HideShow timer Statistics

Club X has more than 10 but fewer than 40 members. Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables, and sometimes they sit at tables with 3 members at one table and 5 members at each of the other tables. If they sit at tables with 6 members at each table except one and fewer than 6 members at that one table, how many members will be at the table that has fewer than 6 members?

Re: Club X has more than 10 but fewer than 40 members. Sometimes [#permalink]

Show Tags

12 Dec 2012, 06:39

22

This post received KUDOS

Expert's post

25

This post was BOOKMARKED

Walkabout wrote:

Club X has more than 10 but fewer than 40 members. Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables, and sometimes they sit at tables with 3 members at one table and 5 members at each of the other tables. If they sit at tables with 6 members at each table except one and fewer than 6 members at that one table, how many members will be at the table that has fewer than 6 members?

(A) 1 (B) 2 (C) 3 (D) 4 (E) 5

3 members at one table and 4 members at each of the other tables, means that the total number of members is 3 more than a multiple of 4: x=4m+3. 3 members at one table and 5 members at each of the other tables, means that the total number of members is 3 more than a multiple of 5: x=5n+3.

Thus x-3 is a multiple of both 4 and 5, so a multiple of 20. Therefore x is 3 more than a multiple of 20. Since 10<x<40, then x=23.

Re: Club X has more than 10 but fewer than 40 members. Sometimes [#permalink]

Show Tags

14 Dec 2012, 03:16

1

This post was BOOKMARKED

Ans:

let the number of people be n , now 10<n<40. Also n=(3+ multiple of 4) and n=(3+ multiple of 5). Therefore n-3 is a multiple of both 4 and 5, one such number is 20. N=23, when 6 members sit at tables then people left are 5, therefore the answer is (E). _________________

Re: Club X has more than 10 but fewer than 40 members. Sometimes [#permalink]

Show Tags

27 Aug 2014, 02:58

I did this the long way, wrote out the seating arrangements possible under each scenario and found that 23 people is the only situation which applies to both seat configurations. Then as the others have pointed out 23 / 6 = 3 remainder 5

Re: Club X has more than 10 but fewer than 40 members. Sometimes [#permalink]

Show Tags

11 Sep 2014, 12:27

Walkabout wrote:

Club X has more than 10 but fewer than 40 members. Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables, and sometimes they sit at tables with 3 members at one table and 5 members at each of the other tables. If they sit at tables with 6 members at each table except one and fewer than 6 members at that one table, how many members will be at the table that has fewer than 6 members?

Re: Club X has more than 10 but fewer than 40 members. Sometimes [#permalink]

Show Tags

30 Oct 2014, 22:54

2

This post received KUDOS

Simple solution quickly would be - E We know that the remainder is 3 in both cases when 4 or 5 people sit --> such one number is 23 (which also is between 20 and 40). And hence, 23/6 gives remainder =5 .

Re: Club X has more than 10 but fewer than 40 members. Sometimes [#permalink]

Show Tags

15 Jun 2015, 18:21

I got 5 as my answer.

For people that are more visual (like me)..

I put a 3 down and another 3 down representing the first two tables, then figured out how many "4s" were needed for the first set and how many "5s" were needed for the second set to add up and equal to the same number for both sets. Since 3 was constant between the two sets, it meant that 4 and 5 needed to have the same number of people, or the LCM, which is 20. Therefore 20 plus 3 is a total of 23 people.

Now you know that the table with a set of 6s needs to add up to 23, but the last table needs to still be less than 6. So the only combination for 6s is 3 tables of 6 people to equal 18 and then a table of 5 people.

Re: Club X has more than 10 but fewer than 40 members. Sometimes [#permalink]

Show Tags

15 Jun 2015, 23:17

1

This post received KUDOS

Expert's post

2

This post was BOOKMARKED

TudorM wrote:

I got tricked by "tables" in the problem stem and I considered more than 1 table of 3 person eacg.

Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables...

Isn't the problem poorly worded?

No, it isn't. This is GMAT language - especially considering that the question is official - and hence you will be required to successfully comprehend such questions.

"Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables,"

The statement explains how the members sit at tables: 3 at ONE table and 4 at EACH of the other tables. Practice questions from the official guide to get comfortable with "GMAT language". _________________

Re: Club X has more than 10 but fewer than 40 members. Sometimes [#permalink]

Show Tags

11 May 2016, 00:35

10<x<40 in both cases 3 members sit on one table remaining members = x-3 so 7<x-3<37 x-3 should be multiple of 4 and 5 to fit all members perfectly on tables. between 7 and 37 only 20 is such number. x-3 = 20 x= 23 If they sit at tables with 6 members at each table except one and fewer than 6 members at that one table => 23/6 remainder ---> 5

Re: Club X has more than 10 but fewer than 40 members. Sometimes [#permalink]

Show Tags

11 May 2016, 07:05

Walkabout wrote:

Club X has more than 10 but fewer than 40 members. Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables, and sometimes they sit at tables with 3 members at one table and 5 members at each of the other tables. If they sit at tables with 6 members at each table except one and fewer than 6 members at that one table, how many members will be at the table that has fewer than 6 members?

(A) 1 (B) 2 (C) 3 (D) 4 (E) 5

Although this problem appears to be a general word problem it is actually testing us on our understanding of remainders when dividing integers. We are first told that the total number of members, which we can denote as “T”, is between 10 and 40. Next, we are told two important pieces of information:

1) “Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables.”

2) “Sometimes they sit at tables with 3 members at one table and 5 members at each of the other tables.”

Let’s now translate these into two mathematical expressions.

1) T/4 = Quotient + Remainder 3

2) T/5 = Quotient + Remainder 3

Because T is being divided by 4 and 5, we are really looking for the following:

T/20 = Quotient + remainder 3.

Since T must be between 10 and 40, there is only one value in that range which, when divided by 20, produces a remainder of 3. That value is 23. We can now use this value to complete the question. We are finally asked:

“If they sit at tables with 6 members at each table except one and fewer than 6 members at that one table, how many members will be at the table that has fewer than 6 members?”

This is same as asking the following: what is the remainder when 23 is divided by 6? We can see that 6 divides into 23 3 times with a remainder of 5.

Answer: E. _________________

Jeffrey Miller Scott Woodbury-Stewart Founder and CEO

Re: Club X has more than 10 but fewer than 40 members. Sometimes [#permalink]

Show Tags

14 May 2016, 22:36

If they sit at tables with 6 members at each table except one and fewer than 6 members at that one table

What does the statement above means? specially the "Except one". I got tricked by it thinking that 22 (23 except 1 or 22-1) members were seated with 6 members at each table

gmatclubot

Re: Club X has more than 10 but fewer than 40 members. Sometimes
[#permalink]
14 May 2016, 22:36

MBA Admission Calculator Officially Launched After 2 years of effort and over 1,000 hours of work, I have finally launched my MBA Admission Calculator . The calculator uses the...

Final decisions are in: Berkeley: Denied with interview Tepper: Waitlisted with interview Rotman: Admitted with scholarship (withdrawn) Random French School: Admitted to MSc in Management with scholarship (...

The London Business School Admits Weekend officially kicked off on Saturday morning with registrations and breakfast. We received a carry bag, name tags, schedules and an MBA2018 tee at...