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# Coffee R 24 pounds, coffee P 25 pounds. Mix these two kinds

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Coffee R 24 pounds, coffee P 25 pounds. Mix these two kinds [#permalink]

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25 Apr 2006, 23:12
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Coffee R 24 pounds, coffee P 25 pounds. Mix these two kinds of coffee to produce mixture X, in which the rate of RtoP is 4:1; and mixture Y, in which the rate of Rto P is 1:3. What is the amount of mixture Y?
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26 Apr 2006, 04:16
amount of mixture Y = 1/4 (24) + 3/4 (25) = 24.75
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05 May 2006, 06:54
do not understand you approach.
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05 May 2006, 07:58
Coffee R 24 pounds, coffee P 25 pounds. Mix these two kinds of coffee to produce mixture X, in which the rate of RtoP is 4:1; and mixture Y, in which the rate of Rto P is 1:3. What is the amount of mixture Y?

R1/P1 = 4/1
R1 = 4P1

R2/P2 = 1/3
R2 = P2/3

R1 + R2 = 24
P1 + P2 = 25

Solving, we get P1 = 4.2
Therefore R1 = 4P1 = 16.8

Mixture X = 16.8 + 4.2 = 21
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07 May 2006, 12:45
remgeo wrote:
Coffee R 24 pounds, coffee P 25 pounds. Mix these two kinds of coffee to produce mixture X, in which the rate of RtoP is 4:1; and mixture Y, in which the rate of Rto P is 1:3. What is the amount of mixture Y?

R1/P1 = 4/1
R1 = 4P1

R2/P2 = 1/3
R2 = P2/3

R1 + R2 = 24
P1 + P2 = 25

Solving, we get P1 = 4.2
Therefore R1 = 4P1 = 16.8

Mixture X = 16.8 + 4.2 = 21

Therefore you mean Mixture Y = 29.4
07 May 2006, 12:45
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