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COMBINATIONS

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Manager
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COMBINATIONS [#permalink] New post 02 Feb 2009, 10:36
q; IN HOW MANY WAYS CAN 8 DIFFERENT BOOKS BE EVENLY DISTRIBUTED BY FOUR PERSONS?

630 840 1260 1830 2520
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SVP
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Re: COMBINATIONS [#permalink] New post 02 Feb 2009, 11:03
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vcbabu wrote:
q; IN HOW MANY WAYS CAN 8 DIFFERENT BOOKS BE EVENLY DISTRIBUTED BY FOUR PERSONS?

630 840 1260 1830 2520


Its same as 4 people selecting 2 books each.

= 8C2*6C2*4C2*2C2 = 1260
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Re: COMBINATIONS [#permalink] New post 02 Feb 2009, 11:36
x2suresh wrote:
vcbabu wrote:
q; IN HOW MANY WAYS CAN 8 DIFFERENT BOOKS BE EVENLY DISTRIBUTED BY FOUR PERSONS?

630 840 1260 1830 2520


Its same as 4 people selecting 2 books each.

= 8C2*6C2*4C2*2C2 = 1260


Nothing to add. :-D
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Re: COMBINATIONS [#permalink] New post 03 Feb 2009, 15:59
vcbabu wrote:
please elaborate




Its same as 4 people selecting 2 books each.

= 8C2*6C2*4C2*2C2 = 1260

You have 8 books and 4 people

= (fist person select 2 out of 8 books) *(second person select 2 out of 6 books) *(third person select 2 out of 4 books) *(fourth person select 2 out of 2 books) *
= 8C2*6C2*4C2*2C2 = 1260
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Re: COMBINATIONS [#permalink] New post 04 Feb 2009, 16:40
Sorry but what is C2 in this problem? Not sure how you came up to 1260.
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Re: COMBINATIONS [#permalink] New post 05 Feb 2009, 00:36
x2suresh wrote:
vcbabu wrote:
please elaborate




Its same as 4 people selecting 2 books each.

= 8C2*6C2*4C2*2C2 = 1260

You have 8 books and 4 people

= (fist person select 2 out of 8 books) *(second person select 2 out of 6 books) *(third person select 2 out of 4 books) *(fourth person select 2 out of 2 books) *
= 8C2*6C2*4C2*2C2 = 1260

Does this not result in 2520?
Manager
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Re: COMBINATIONS [#permalink] New post 05 Feb 2009, 04:26
Agree with 1260. What is the OA?
Manager
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Re: COMBINATIONS [#permalink] New post 05 Feb 2009, 04:27
Agree with 1260. What is the OA?
Manager
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Re: COMBINATIONS [#permalink] New post 07 Feb 2009, 10:18
botirvoy wrote:
x2suresh wrote:
vcbabu wrote:
please elaborate




Its same as 4 people selecting 2 books each.

= 8C2*6C2*4C2*2C2 = 1260

You have 8 books and 4 people

= (fist person select 2 out of 8 books) *(second person select 2 out of 6 books) *(third person select 2 out of 4 books) *(fourth person select 2 out of 2 books) *
= 8C2*6C2*4C2*2C2 = 1260

Does this not result in 2520?

I agee. The result of that is 2520, not 1260.
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Re: COMBINATIONS [#permalink] New post 07 Feb 2009, 12:06
Yeap!! it should be 2520
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Re: COMBINATIONS   [#permalink] 07 Feb 2009, 12:06
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