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# company

Author Message
VP
Joined: 18 May 2008
Posts: 1286
Followers: 16

Kudos [?]: 411 [0], given: 0

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03 Feb 2009, 03:22
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

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SVP
Joined: 07 Nov 2007
Posts: 1820
Location: New York
Followers: 34

Kudos [?]: 867 [0], given: 5

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03 Feb 2009, 04:42
ritula wrote:

Z = full time
z = parttime
X = full time
x = part time

question X/x >Z/z?

X+Y/(x+y) = Z/z

1) Y/y < Z/z

--> means X/x>Z/z to satisfy X+Y/(x+y) = Z/z

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VP
Joined: 18 May 2008
Posts: 1286
Followers: 16

Kudos [?]: 411 [0], given: 0

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03 Feb 2009, 09:57
Perfect. OA is D indeed
x2suresh wrote:
ritula wrote:

Z = full time
z = parttime
X = full time
x = part time

question X/x >Z/z?

X+Y/(x+y) = Z/z

1) Y/y < Z/z

--> means X/x>Z/z to satisfy X+Y/(x+y) = Z/z

Senior Manager
Joined: 08 Jan 2009
Posts: 329
Followers: 2

Kudos [?]: 149 [0], given: 5

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09 Feb 2009, 10:29
Can u please explain this.I didnt get you.

About statement 2 no exp was given.
Re: company   [#permalink] 09 Feb 2009, 10:29
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# company

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