Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Company A's workforce consists of 10 percent managers and 90 [#permalink]
09 Sep 2012, 01:25

2

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

45% (medium)

Question Stats:

71% (02:48) correct
29% (01:43) wrong based on 188 sessions

Company A's workforce consists of 10 percent managers and 90 percent software engineers. Company B's workforce consists of 30 percent managers, 10 percent software engineers, and 60 percent support staff. The two companies merge, every employee stays with the resulting company, and no new employees are added. If the resulting companyís workforce consists of 25 percent managers, what percent of the workforce originated from Company A?

EXPL: The question gives you two equations. First, the percents of the managers, where A and B stand for the total number of employees in each companyís workforce: 1/10 (A) + 3/10 B = 1 /4 (A + B) Since A and B are fractions (or percents) of the total resulting workforce: A+B=1 To combine the equations, rewrite the second equation: A=1- B Then plug in to the first equation

I am not clear that how can A and B be treated as fractions when they represent the number of employees in firms A and B respectively. How is A+B =1?

Re: mixtures problem [#permalink]
09 Sep 2012, 01:53

1

This post received KUDOS

adineo wrote:

Company A's workforce consists of 10 percent managers and 90 percent software engineers. Company B's workforce consists of 30 percent managers, 10 percent software engineers, and 60 percent support staff. The two companies merge, every employee stays with the resulting company, and no new employees are added. If the resulting companyís workforce consists of 25 percent managers, what percent of the workforce originated from Company A? (A) 10% (B) 20% (C) 25% (D) 50% (E) 75%

EXPL: The question gives you two equations. First, the percents of the managers, where A and B stand for the total number of employees in each companyís workforce: 1/10 (A) + 3/10 B = 1 /4 (A + B) Since A and B are fractions (or percents) of the total resulting workforce: A+B=1 To combine the equations, rewrite the second equation: A=1- B Then plug in to the first equation

I am not clear that how can A and B be treated as fractions when they represent the number of employees in firms A and B respectively. How is A+B =1?

Let say Company A has x employes and B has y employees. Now they merge and total no of employees = x+y employees.

Per the question Company A's workforce consists of 10 percent managers and 90 percent software engineers. Company B's workforce consists of 30 percent managers, 10 percent software engineers, and 60 percent support staff. We translate it into equation as follows:

.1x + .3y = .25 (x+y) => x + 3y =2.5 (x+y) => .5y = 1.5x => y=3x. Now we know total employee = x+y. we need to find %age of x in total (x+y) ie x/(x+y) X100% => x/(3x+x) [substitute y=3x] => x/4x X 100% => .25 X 100 % => 25%.

Re: Company A's workforce consists of 10 percent managers and 90 [#permalink]
09 Sep 2012, 03:26

3

This post received KUDOS

Expert's post

Company A's workforce consists of 10 percent managers and 90 percent software engineers. Company B's workforce consists of 30 percent managers, 10 percent software engineers, and 60 percent support staff. The two companies merge, every employee stays with the resulting company, and no new employees are added. If the resulting companyís workforce consists of 25 percent managers, what percent of the workforce originated from Company A?

(A) 10% (B) 20% (C) 25% (D) 50% (E) 75%

Say \(a\) is the number of employees in company A and \(b\) is the number of employees in company B.

The question is: "what percent of the workforce originated from Company A", so we should find the value of \(\frac{a}{a+b}\).

We are told that 10% managers from A and 30% managers from B result in 25% managers in combined workforce, hence \(0.1a+0.3b=0.25(a+b)\) --> \(b=3a\) --> \(\frac{a}{a+b}=\frac{1}{4}=0.25\).

Re: Company A's workforce consists of 10 percent managers and 90 [#permalink]
09 Sep 2012, 04:04

1

This post received KUDOS

adineo wrote:

Company A's workforce consists of 10 percent managers and 90 percent software engineers. Company B's workforce consists of 30 percent managers, 10 percent software engineers, and 60 percent support staff. The two companies merge, every employee stays with the resulting company, and no new employees are added. If the resulting companyís workforce consists of 25 percent managers, what percent of the workforce originated from Company A?

As, it is given that final % of managers is 25%, so we can say 10% of C1 and 30% of C2 constitute 25% of managers in merged company. Now, let's arrange the algorithm-

---------------10--------------------------------------30 -------------------------------------25 ----------------5 (=30-25)------------------------15 (=25-15) [Calculate difference diagonally; also this is the ratio of two companies] ----------------1--------------------------------------3 (Ratio remains same after dividing both 5, and 15 with 5)

This means, Company C1 has as share of \(1 / (1+3)\) \(= 1/4\)\(= 25%\)

So, the answer is C _________________

My mantra for cracking GMAT: Everyone has inborn talent, however those who complement it with hard work we call them 'talented'.

+1 Kudos = Thank You Dear Are you saying thank you?

Re: Company A's workforce consists of 10 percent managers and 90 [#permalink]
09 Sep 2012, 07:05

Thanks for the solutions guys.

I had a doubt regarding the solution i have supplied under the spoiler. In that A and B are considered as the number of employees in step one and in the next step as fractions/ratios, and we get the answer that way also. Can you please explain that?

Re: Company A's workforce consists of 10 percent managers and 90 [#permalink]
10 Sep 2012, 02:35

3

This post received KUDOS

Expert's post

adineo wrote:

Thanks for the solutions guys.

I had a doubt regarding the solution i have supplied under the spoiler. In that A and B are considered as the number of employees in step one and in the next step as fractions/ratios, and we get the answer that way also. Can you please explain that?

Actually, they are assuming that A represents the fraction of workforce of A in the total workforce and B represents the fraction of workforce of B in the total workforce.

A and B do not stand for the number of employees.

The method they have used is not the most optimum. Use weighted avg formula instead. You know that company A has 10% managers and company B has 30% managers and together they have 25% managers.

Re: Company A's workforce consists of 10 percent managers and 90 [#permalink]
10 Sep 2012, 20:28

Bunuel wrote:

Company A's workforce consists of 10 percent managers and 90 percent software engineers. Company B's workforce consists of 30 percent managers, 10 percent software engineers, and 60 percent support staff. The two companies merge, every employee stays with the resulting company, and no new employees are added. If the resulting companyís workforce consists of 25 percent managers, what percent of the workforce originated from Company A?

(A) 10% (B) 20% (C) 25% (D) 50% (E) 75%

Say \(a\) is the number of employees in company A and \(b\) is the number of employees in company B.

The question is: "what percent of the workforce originated from Company A", so we should find the value of \(\frac{a}{a+b}\).

We are told that 10% managers from A and 30% managers from B result in 25% managers in combined workforce, hence \(0.1a+0.3b=0.25(a+b)\) --> \(b=3a\) --> \(\frac{a}{a+b}=\frac{1}{4}=0.25\).

It is clear thanks, and i have used the same method while solving this question, however i had a big doubt before chosing the answer. I started to look at the other part of the provided information. Eventhough i did not used it and i think it is not of much need here, but still i thought since it is given there should be some purpose. My question, does the GMAT sometimes use information just to distract or i am missing something? _________________

If you found my post useful and/or interesting - you are welcome to give kudos!

Re: Company A's workforce consists of 10 percent managers and 90 [#permalink]
11 Sep 2012, 01:43

Expert's post

ziko wrote:

Bunuel wrote:

Company A's workforce consists of 10 percent managers and 90 percent software engineers. Company B's workforce consists of 30 percent managers, 10 percent software engineers, and 60 percent support staff. The two companies merge, every employee stays with the resulting company, and no new employees are added. If the resulting companyís workforce consists of 25 percent managers, what percent of the workforce originated from Company A?

(A) 10% (B) 20% (C) 25% (D) 50% (E) 75%

Say \(a\) is the number of employees in company A and \(b\) is the number of employees in company B.

The question is: "what percent of the workforce originated from Company A", so we should find the value of \(\frac{a}{a+b}\).

We are told that 10% managers from A and 30% managers from B result in 25% managers in combined workforce, hence \(0.1a+0.3b=0.25(a+b)\) --> \(b=3a\) --> \(\frac{a}{a+b}=\frac{1}{4}=0.25\).

It is clear thanks, and i have used the same method while solving this question, however i had a big doubt before chosing the answer. I started to look at the other part of the provided information. Eventhough i did not used it and i think it is not of much need here, but still i thought since it is given there should be some purpose. My question, does the GMAT sometimes use information just to distract or i am missing something?

Yes, I've seen some questions from reliable sources which had redundant information just to confuse us. _________________

More:"All I wish someone had told me about GMAT beforehand" There are many things you want to know before doing the GMAT exam (how is exam day, what to expect, how to think, to do's...), and you have them in this blog, in a simple way

Last edited by johnwesley on 22 Mar 2013, 15:44, edited 1 time in total.

Re: Company As workforce consists of 10 percent managers and 90 [#permalink]
21 Mar 2013, 18:06

Expert's post

It's trueeeeeeeee

I'm always comfortable with these problems , even the most difficult but at 2.00 AM is not a big deal

0.1 X + 0.3 Y = 0.25 (X + Y )

Now 15 X = 5 Y ---> X / Y = 5/15 = 1/3 \(BUT\) the ration 1 : 3 is = to 4 (the total) so the parts must be 1/4 and 3/4. We care about of X so 1/4 = 25.

Re: Company As workforce consists of 10 percent managers and 90 [#permalink]
21 Mar 2013, 18:20

1. Let the total number of worforce of the resulting company be 100. 2. Let us say x number of the workforce originated from A. 3. 10 % of that number is the number of managers contributed by A which is\(x/10\). 4. (100-x) of the workforce originated from B. 5. 30 % of that number is the number of managers contributed by B which is\(3(100-x)/10\) 6. We have the total number of managers in the resulting company as 25. 7. (3) + (5) =(6) i.e.,\(x/10 + 3(100-x)/10 = 25\) x=25.

Re: Company As workforce consists of 10 percent managers and 90 [#permalink]
21 Mar 2013, 20:30

1

This post received KUDOS

Expert's post

carcass wrote:

Company As workforce consists of 10 percent managers and 90 percent software engineers. Company Bs workforce consists of 30 percent managers, 10 percent software engineers, and 60 percent support sta¤. The two companies merge, every employee stays with the resulting company, and no new employees are added. If the resulting companys workforce consists of 25 percent managers, what percent of the workforce originated from Company A?

(A) 10% (B) 20% (C) 25% (D) 50% (E) 75%

I'm not fully convinced by OA.

If the two companies are merged and supposed that we have 200 people, then 25 % of 200 is 50. So. 50 people are manager (if I understand correct).

Now the problem asks: what % of this 50 comes from company A................let me know. Thanks

Use weighted avgs here. Company A has 10% managers and company B has 30% managers. Overall, the merged company has 25% managers. So what is the ratio number of employees of company A to number of employees of company B?

number of employees of company A:number of employees of company B = (30 - 25):(25 - 10) = 1:3

What percent of the workforce originated from Company A? 1/4 = 25% _________________

Re: mixtures problem [#permalink]
10 Mar 2014, 23:27

SOURH7WK wrote:

adineo wrote:

Company A's workforce consists of 10 percent managers and 90 percent software engineers. Company B's workforce consists of 30 percent managers, 10 percent software engineers, and 60 percent support staff. The two companies merge, every employee stays with the resulting company, and no new employees are added. If the resulting companyís workforce consists of 25 percent managers, what percent of the workforce originated from Company A? (A) 10% (B) 20% (C) 25% (D) 50% (E) 75%

EXPL: The question gives you two equations. First, the percents of the managers, where A and B stand for the total number of employees in each companyís workforce: 1/10 (A) + 3/10 B = 1 /4 (A + B) Since A and B are fractions (or percents) of the total resulting workforce: A+B=1 To combine the equations, rewrite the second equation: A=1- B Then plug in to the first equation

I am not clear that how can A and B be treated as fractions when they represent the number of employees in firms A and B respectively. How is A+B =1?

Let say Company A has x employes and B has y employees. Now they merge and total no of employees = x+y employees.

Per the question Company A's workforce consists of 10 percent managers and 90 percent software engineers. Company B's workforce consists of 30 percent managers, 10 percent software engineers, and 60 percent support staff. We translate it into equation as follows:

.1x + .3y = .25 (x+y) => x + 3y =2.5 (x+y) => .5y = 1.5x => y=3x. Now we know total employee = x+y. we need to find %age of x in total (x+y) ie x/(x+y) X100% => x/(3x+x) [substitute y=3x] => x/4x X 100% => .25 X 100 % => 25%.

Re: Company A's workforce consists of 10 percent managers and 90 [#permalink]
11 Mar 2014, 00:31

General solution for mixture problems.

In this type of problems S1 consisting of some components and S2 consisting of one or more of the same components are mixed

Steps:

1.Identify the S1 and S2 and their components. For simplicity let us assume S1 and S2 are solutions. They may also be solids such as bars.

2.S1 and S2 are identified as follows:

(i)S1 and S2 are explicitly mentioned as two different solutions. (ii)S1 is the original solution. S2 is the same type of solution but added to S1. The elements become added in the proportion they are present (iii)S1 is the original solution and S2 is a different type of solution and may contain only one element ,such as water. This element will be present in S1 also. (iv)S1 is the original solution and S2 is the same type of solution got from removing some quantity from S1. The elements are removed in the same proportion they are present. (v)S1 is the original solution and S2 is that which is got by removing only one element from S1. (vi)S1 and S2 are two solutions and they contain only one element or only one element is mentioned.

where re1/re2 is the ratio of the elements in the result after s1 and s2 are mixed, s1 and s2 are the quantity of the solutions . The elements in each solution are normally given in ratios.

I am not panicking. Nope, Not at all. But I am beginning to wonder what I was thinking when I decided to work full-time and plan my cross-continent relocation...

Over the last week my Facebook wall has been flooded with most positive, almost euphoric emotions: “End of a fantastic school year”, “What a life-changing year it’s been”, “My...