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Company P had 15 percent more employees in December than it [#permalink]

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08 Oct 2012, 01:49

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30% (01:30) wrong based on 818 sessions

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Company P had 15 percent more employees in December than it had in January. If Company P had 460 employees in December, how many employees did it have in January?

(A) 391 (B) 400 (C) 410 (D) 423 (E) 445

Practice Questions Question: 57 Page: 159 Difficulty: 550

Re: Company P had 15 percent more employees in December than it [#permalink]

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08 Oct 2012, 01:50

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SOLUTION

Company P had 15 percent more employees in December than it had in January. If Company P had 460 employees in December, how many employees did it have in January?

Re: Company P had 15 percent more employees in December than it [#permalink]

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08 Oct 2012, 04:39

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Bunuel wrote:

Company P had 15 percent more employees in December than it had in January. If Company P had 460 employees in December, how many employees did it have in January?

(A) 391 (B) 400 (C) 410 (D) 423 (E) 445

Since \(15%=\frac{15}{100}=\frac{3}{20}\), it means that \(460\) represents \(23/20\) of the number of employees in January. Then, \(1/20\) of that number is \(460/23 = 20.\) Therefore, the number of employees in January was \(20\cdot20=400.\)

Answer B.

PS Bunuel, just another small typo...see above (slution). And I am mad at myself, why I didn't see it before... _________________

PhD in Applied Mathematics Love GMAT Quant questions and running.

Last edited by EvaJager on 08 Oct 2012, 07:11, edited 2 times in total.

Re: Company P had 15 percent more employees in December than it [#permalink]

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08 Oct 2012, 04:53

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If J = # of employees in January, and D = # of employees in December.. D = (J + 15% of J) = (1.15)*J Plug in known values (D = 460) Therefore, (1.15)*J = 460 Solve for J J = 460/(1.15) = 400 B _________________

Re: Company P had 15 percent more employees in December than it [#permalink]

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08 Oct 2012, 06:49

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Let the no. of employees in Jan=x Therefore the no.of employees in Dec will be =Total employees in Jan PLUS increased no of employees =>{x + (15% of x)} => 1.15x

It is given that; Total no.of employees in Dec = 460 so, 1.15x=460 solve for x , we will get x= 400

Answer: B _________________

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Re: Company P had 15 percent more employees in December than it [#permalink]

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09 Oct 2012, 22:05

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First, we need to determine which one to use for base January or December, that is whether, J= 1.15D Or 0.85J = D

The question says . employees in December are 15% more than in January. Therefore we are actually taking J as base and hence get number of employees in December as D=115% of J => 1.15J Or 1.15J =460 => J =400 Ans (B) _________________

Re: Company P had 15 percent more employees in December than it [#permalink]

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11 Oct 2012, 03:39

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please. experts can give an opinion about the level (real) of this question ?? of course I know that is not important the level but to solve it 300 or 700 no matter what

back to question.

J --------------- D

X 1.15

1.15 x = 460 X = 400 B in 30 seconds ( thanks to sleepless nights)

or 1.15 is what % of 460 ----> translate 1.15 = x/100 * 460 -----> = 4 only B fits the bill

C should not possible following this process of reasoning _________________

Re: Company P had 15 percent more employees in December than it [#permalink]

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11 Oct 2012, 13:22

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SOLUTION

Company P had 15 percent more employees in December than it had in January. If Company P had 460 employees in December, how many employees did it have in January?

Re: Company P had 15 percent more employees in December than it [#permalink]

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16 Feb 2013, 12:19

Okay, so now i ve fallen into this really Stupid trap here . I got A) 391 . 15% of 460 is 69 . So i did 460-69 = 391 . I know i am wrong now and this is a dumb mistake . But what am i missing here ?? Kindly Help.. Thanks in Advance

Re: Company P had 15 percent more employees in December than it [#permalink]

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16 Feb 2013, 12:57

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thinktank wrote:

Okay, so now i ve fallen into this really Stupid trap here . I got A) 391 . 15% of 460 is 69 . So i did 460-69 = 391 . I know i am wrong now and this is a dumb mistake . But what am i missing here ?? Kindly Help.. Thanks in Advance

If 100 is increased by 50%, we get 150. However if 150 is decreased by 50% we do not get 100 and instead we get 75. The mistake you are doing is thinking that a 15% decrease from 460 is the same as a 15% increase from the right answer choice. From the above illustration, we can see that equating as such is incorrect. _________________

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Re: Company P had 15 percent more employees in December than it [#permalink]

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17 Feb 2013, 21:26

MacFauz wrote:

thinktank wrote:

Okay, so now i ve fallen into this really Stupid trap here . I got A) 391 . 15% of 460 is 69 . So i did 460-69 = 391 . I know i am wrong now and this is a dumb mistake . But what am i missing here ?? Kindly Help.. Thanks in Advance

If 100 is increased by 50%, we get 150. However if 150 is decreased by 50% we do not get 100 and instead we get 75. The mistake you are doing is thinking that a 15% decrease from 460 is the same as a 15% increase from the right answer choice. From the above illustration, we can see that equating as such is incorrect.

Re: Company P had 15 percent more employees in December than it [#permalink]

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28 Oct 2013, 21:53

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thinktank wrote:

Okay, so now i ve fallen into this really Stupid trap here . I got A) 391 . 15% of 460 is 69 . So i did 460-69 = 391 . I know i am wrong now and this is a dumb mistake . But what am i missing here ?? Kindly Help.. Thanks in Advance

I solved the problem by estimation, I won't try to explain that, just for the fact that 410 could be a trap. So I'll try to explain on BackSolving the problem.

Re: Company P had 15 percent more employees in December than it [#permalink]

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25 May 2014, 14:05

Bunuel wrote:

Company P had 15 percent more employees in December than it had in January. If Company P had 460 employees in December, how many employees did it have in January?

(A) 391 (B) 400 (C) 410 (D) 423 (E) 445

Practice Questions Question: 57 Page: 159 Difficulty: 550

I'm having a problem. I started solving this problem when December is x and January is 0.85x. IF x=460 shouldn't January be 460x0.85=391

Re: Company P had 15 percent more employees in December than it [#permalink]

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25 May 2014, 14:17

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bytatia wrote:

Bunuel wrote:

Company P had 15 percent more employees in December than it had in January. If Company P had 460 employees in December, how many employees did it have in January?

(A) 391 (B) 400 (C) 410 (D) 423 (E) 445

I'm having a problem. I started solving this problem when December is x and January is 0.85x. IF x=460 shouldn't January be 460x0.85=391

Where am I going wrong?

x is 15% more than y means, that \(x=1.15y\), or that \(y=\frac{x}{1.15}\approx{0.87x}\).

\(y=0.85x\) means that y is 15% less than x, which is not the same as x is 15% more than y. _________________

Re: Company P had 15 percent more employees in December than it [#permalink]

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21 May 2016, 08:22

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