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Compilation of tips and tricks to deal with remainders.

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New post 08 Nov 2012, 21:52
thanks you very much for the very very useful post
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New post 17 Jan 2013, 11:53
hey would someone rephrase whole of point number 4) Cycle of powers...am failing to understand,especially with the sub points from 2 to 10,what is happening over there..would sbdy pls explain to me with an impeccable explaination.

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New post 26 Apr 2013, 13:44
Forum, request to help me understand Rule 4. powers of 10...I dont follow this at all.
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New post 10 Jul 2013, 23:07
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New post 11 Jul 2013, 01:09
Keep the good work..just brushing with my basics...this will definitely help me..
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New post 24 Jul 2013, 09:16
Ponit 5 and 6 can be simplified to the following non-formula approach

if x and y and two integer and they are divided by the same no. then you can multiply the remainder of two or more integers directly and then divide the product of the remainders by the divisor to get the reminder for the product of the integers.

e.g if x leaves a remainder 5 upon division by 9 and y leaves a reminder 7 upon division by 9 then x will leave the remainder 7*5/9 (multiply the reminders and then divide by 9). which is 8

similarly

remainders can be added and subtracted directly if the divisor of two or more integers is the same.

e.g
if x leaves a remainder 5 on division by 8 and y leaves a remainder 6 on division by 8 then X-Y will leave remainder 5-6/8=-1/8 will leave a remainder of 7. simply subtract the remainders and then divide by the divisor.

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New post 15 Apr 2014, 21:53
Great Post Loved it. I have major problem in solving reminder problems. Shriharimurthy, Can you please explain tip 4, 5 and 6 with better examples. I mean little more complicated examples please. Like GMAT questions.

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New post 08 Aug 2014, 03:26
Brilliant .... I loved this post
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New post 31 Dec 2014, 12:00
Can somebody help me out ?

In number 6, the formula and example does not the same, the extra "n" in formula is not apply to example
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New post 03 Aug 2015, 01:59
An easy way to understand Number Tree:
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New post 02 Jan 2016, 09:22
This is an awesome thread! Bumping it up so that new people find it.
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New post 06 Feb 2016, 10:04
I guess there is something wrong with formula 5 and 6. Can anybody please explain these two formula with more clear elaboration?
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New post 13 May 2016, 00:06
It is a great post. Can you please also add some more example question that you think is common for gmat
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sriamlan wrote:
It is a great post. Can you please also add some more example question that you think is common for gmat


Check the links on remainders below:
Divisibility and Remainders on the GMAT

Theory on remainders problems

Tips on remainders

Cyclicity on the GMAT

Units digits, exponents, remainders problems

Also, go through the following post ALL YOU NEED FOR QUANT ! ! !.

Hope it helps.
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New post 25 Sep 2016, 10:21
sriharimurthy wrote:
Quote:
Could you, please, explain the solution? I didn't get it.

I found out that the remaider is 3; should we just pick up the answer to get multiple of 3?


Hi Shelen,

In the question, it is given that s/t = 64.12

Thus, we know that the remainder in decimal format will be 0.12
(Note : Do not make the mistake of considering it to be 12. It is 0.12)

Now, we know that the answer should be a multiple of 0.12 since 'the remainder of s/t' will be equal to 'the remainder of s/t in decimal format' multiplied by 't'.

That is, R of (s/t) = 0.12*t ----> which is a multiple of 0.12 for all the positive integer values that 't' can hold.

Now, in order to make the calculation simpler, we can multiply both sides of the equation by 100.

R*100 = 12*t --> t = (R*100)/12

Now, since it is given that 't' is a positive integer, (R*100) has to be perfectly divisible by 12.

Thus look through the answer choices to see which one satisfies this condition.

You will find that R = 45 will be the only one that satisfies it, since 4500 is perfectly divisible by 12.

Therefore answer is choice (E) which is 45.



I did this with different approach.
s/t= 64.12 = 6412/100= 1603/25
=>Remainder= 3

=> Correct answer should be a multiple of 3. Only choice (E)45 is multiple of 3
Hence (E)

Is this approach correct??
Re: Compilation of tips and tricks to deal with remainders.   [#permalink] 25 Sep 2016, 10:21

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