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Compilation of tips and tricks to deal with remainders. [#permalink]
11 Nov 2009, 15:33
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Hi guys, This is in conjunction with another post which has questions dealing with remainders (collection-of-remainder-problems-in-gmat-74776.html). I'm just trying to put together a list of tips and tricks which we can use to solve these kind of problems with greater accuracy and speed. Please feel free to comment and make suggestions. Hopefully we can add onto this list and cover all sorts of strategies that would help us deal with remainders! Cheers.
Please read this first : 1) Take your time with these points. Some of them might be a little difficult to follow in the first reading, but don't give up. The concepts are fairly simple. 2) These tips if mastered will be extremely valuable in the GMAT to help solve a variety of questions not limited specifically to remainders. I have been using them for quite a while now and they have not only helped me improve my accuracy but also my speed. 3) If you have any doubts, please do not hesitate to ask (no matter how stupid you might think them to be!). If you do not ask, you will never learn. 4) Lastly, have fun while trying to understand these tips and tricks as that, according to me, is the best possible way to learn.
All the best!
-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x-x- NOTE: Where ever you see R of 'x' it just stands for Remainder of x.
1) The possible remainders when a number is divided by ‘n’ can range from 0 to (n-1). Eg. If n=10, possible remainders are 0,1,2,3,4,5,6,7,8 and 9.
2) If a number is divided by 10, its remainder is the last digit of that number. If it is divided by 100 then the remainder is the last two digits and so on. This is good for questions such as : ' What is the last digit of.....' or ' What are the last two digits of.....' .
3) If a number leaves a remainder ‘r’ (the number is the divisor), all its factors will have the same remainder ‘r’ provided the value of ‘r’ is less than the value of the factor. Eg. If remainder of a number when divided by 21 is 5, then the remainder of that same number when divided by 7 (which is a factor of 21) will also be 5.
If the value of ‘r’ is greater than the value of the factor, then we have to take the remainder of ‘r’ divided by the factor to get the remainder. Eg. If remainder of a number when divided by 21 is 5, then the remainder of that same number when divided by 3 (which is a factor of 21) will be remainder of 5/3, which is 2.
4) Cycle of powers : This is used to find the remainder of \(n^x\), when divided by 10, as it helps us in figuring out the last digit of \(n^x\).
The cycle of powers for numbers from 2 to 10 is given below:
2: 2, 4, 8, 6 → all \(2^{4x}\) will have the same last digit.
3: 3, 9, 7, 1 → all \(3^{4x}\) will have the same last digit.
4: 4, 6 → all \(4^{2x}\) will have the same last digit.
5: 5 → all \(5^x\) will have the same last digit.
6: 6 → all \(6^x\) will have the same last digit.
7: 7, 9, 3, 1 → all \(7^{4x}\) will have the same last digit.
8: 8, 4, 2, 6 → all \(8^{4x}\) will have the same last digit.
9: 9, 1 → all \(9^{2x}\) will have the same last digit.
10: 0 → all \(10^x\) will have the same last digit.
5) Many seemingly difficult remainder problems can be simplified using the following formula : \(R of \frac{x*y}{n} = R of \frac{(R of \frac{x}{n})*(R of \frac{y}{n})}{n}\)
Eg. \(R of \frac{20*27}{25} = R of \frac{(R of \frac{20}{25})*(R of \frac{27}{25})}{25} = R of \frac{(20)*(2)}{25} = R of \frac{40}{25} = 15\)
Eg. \(R of \frac{225}{13} = R of \frac{(15)*(15)}{13} = R of {(2)*(2)}{13} = R of \frac{4}{13} = 4\)
6) \(R of \frac{x*y}{n}\) , can sometimes be easier calculated if we take it as \(R of \frac{(R of \frac{(x-n)}{n})*(R of \frac{(y-n)}{n})}{n}\) Especially when x and y are both just slightly less than n. This can be easier understood with an example:
Eg. \(R of \frac{(19)*(21)}{25} = R of \frac{(-6)*(-4)}{25} = 24\)
NOTE: Incase the answer comes negative, (if x is less than n but y is greater than n) then we have to simply add the remainder to n.
Eg. \(R of \frac{(23)*(27)}{25} = R of \frac{(-2)*(2)}{25} = -4.\) Now, since it is negative, we have to add it to 25.\(R = 25 + (-4) = 21\)
[Note: Go here to practice two good problems where you can use some of these concepts explained : numbers-86325.html]
7) If you take the decimal portion of the resulting number when you divide by "n", and multiply it to "n", you will get the remainder. [Special thanks to h2polo for this one]
Note: Converse is also true. If you take the remainder of a number when divided by 'n', and divide it by 'n', it will give us the remainder in decimal format.
Eg. \(\frac{8}{5} = 1.6\)
In this case, \(0.6 * 5 = 3\)
Therefore, the remainder is \(3\).
This is important to understand for problems like the one below:
If s and t are positive integer such that s/t=64.12, which of the following could be the remainder when s is divided by t? (A) 2 (B) 4 (C) 8 (D) 20 (E) 45
Re: Compilation of tips and tricks to deal with remainders. [#permalink]
14 Nov 2009, 04:54
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Here is another important property about reminders that everyone should understand:
If you take the decimal portion of the resulting number when you divide by "n", and multiply it to "n", you will get the remainder.
For example, 8/5 = 1.6
.6 * 5 = 3
Therefore, the remainder is 3.
This is important to understand for problems like the one below:
If s and t are positive integer such that s/t=64.12, which of the following could be the remainder when s is divided by t? (A) 2 (B) 4 (C) 8 (D) 20 (E) 45
Re: Compilation of tips and tricks to deal with remainders. [#permalink]
14 Nov 2009, 05:08
4
This post received KUDOS
h2polo wrote:
Here is another important property about reminders that everyone should understand:
If you take the decimal portion of the resulting number when you divide by "n", and multiply it to "n", you will get the remainder.
For example, 8/5 = 1.6
.6 * 5 = 3
Therefore, the remainder is 3.
This is important to understand for problems like the one below:
If s and t are positive integer such that s/t=64.12, which of the following could be the remainder when s is divided by t? (A) 2 (B) 4 (C) 8 (D) 20 (E) 45
Re: Compilation of tips and tricks to deal with remainders. [#permalink]
15 Nov 2009, 04:57
3
This post received KUDOS
1
This post was BOOKMARKED
ctrlaltdel wrote:
If s and t are positive integer such that s/t=64.12, which of the following could be the remainder when s is divided by t? (A) 2 (B) 4 (C) 8 (D) 20 (E) 45
Ans: Using the technique: remainder = 0.12*t => the answer is multiple of 12. but none of the options match...did i miss something or is my understanding wrong
Don't worry. This question is not that straightforward but understanding it will really help you for any other such question.
The answer is a multiple of 0.12.
However, If we consider it to be a multiple of 12, then we have to multiply each of the answers by 100 and then check.
Try working it out now.
You should get the answer to be (E). If you face any further difficulties then feel free to ask again! _________________
Re: Compilation of tips and tricks to deal with remainders. [#permalink]
19 Nov 2009, 01:45
3
This post received KUDOS
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Quote:
Could you, please, explain the solution? I didn't get it.
I found out that the remaider is 3; should we just pick up the answer to get multiple of 3?
Hi Shelen,
In the question, it is given that s/t = 64.12
Thus, we know that the remainder in decimal format will be 0.12 (Note : Do not make the mistake of considering it to be 12. It is 0.12)
Now, we know that the answer should be a multiple of 0.12 since 'the remainder of s/t' will be equal to 'the remainder of s/t in decimal format' multiplied by 't'.
That is, R of (s/t) = 0.12*t ----> which is a multiple of 0.12 for all the positive integer values that 't' can hold.
Now, in order to make the calculation simpler, we can multiply both sides of the equation by 100.
R*100 = 12*t --> t = (R*100)/12
Now, since it is given that 't' is a positive integer, (R*100) has to be perfectly divisible by 12.
Thus look through the answer choices to see which one satisfies this condition.
You will find that R = 45 will be the only one that satisfies it, since 4500 is perfectly divisible by 12.
Therefore answer is choice (E) which is 45. _________________
Re: Practice these tricks! [#permalink]
30 Dec 2009, 08:12
1
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R2I4D wrote:
Practice sri's wonderful tips and tricks: 4GMAT Home >> GMAT Test Prep Questions >> Number Systems...
(Can't post hyperlinks yet, sorry!)
I was wondering if someone could show me how to do this problem (found at the said site) quicker than my method (detailed below):
8. What is the remainder when the product of 1044, 1047, 1050, and 1053 is divided by 33?
I used sri's trick and found that 1056 is a multiple of 33. This resulted in remainders of (-12)(-9)(-6)(-3), respectively. Multiplied together, you get 1944. The remainder of 1944, when divided by 33, is 30, the correct answer.
Is there a quicker way than multiplying (-12)(-9)(-6)(-3) out?
Thanks, in advance!
Hi,
Im glad you found these tips helpful. There is in fact a quicker way to solve it.
R of \(\frac{(-12)*(-3)*(-9)*(-6)}{33}\) = R of \(\frac{(36)*(54)}{33}\) = R of \(\frac{(3)*(21)}{33}\) = R of \(\frac{63}{33}\) = \(30\)
As you can see, you don't really need to do any complex multiplications. Just multiply numbers is groups that yield a number closest to the denominator. That way you can keep simplifying to smaller numbers and avoid big calculations.
Re: Compilation of tips and tricks to deal with remainders. [#permalink]
15 Nov 2009, 04:47
If s and t are positive integer such that s/t=64.12, which of the following could be the remainder when s is divided by t? (A) 2 (B) 4 (C) 8 (D) 20 (E) 45
Ans: Using the technique: remainder = 0.12*t => the answer is multiple of 12. but none of the options match...did i miss something or is my understanding wrong
Re: Compilation of tips and tricks to deal with remainders. [#permalink]
19 Nov 2009, 01:19
sriharimurthy wrote:
ctrlaltdel wrote:
If s and t are positive integer such that s/t=64.12, which of the following could be the remainder when s is divided by t? (A) 2 (B) 4 (C) 8 (D) 20 (E) 45
Ans: Using the technique: remainder = 0.12*t => the answer is multiple of 12. but none of the options match...did i miss something or is my understanding wrong
Don't worry. This question is not that straightforward but understanding it will really help you for any other such question.
The answer is a multiple of 0.12.
However, If we consider it to be a multiple of 12, then we have to multiply each of the answers by 100 and then check.
Try working it out now.
You should get the answer to be (E). If you face any further difficulties then feel free to ask again!
Could you, please, explain the solution? I didn't get it.
I found out that the remaider is 3; should we just pick up the answer to get multiple of 3?
Re: Compilation of tips and tricks to deal with remainders. [#permalink]
19 Nov 2009, 02:37
sriharimurthy wrote:
Quote:
Could you, please, explain the solution? I didn't get it.
I found out that the remaider is 3; should we just pick up the answer to get multiple of 3?
Hi Shelen,
In the question, it is given that s/t = 64.12
Thus, we know that the remainder in decimal format will be 0.12 (Note : Do not make the mistake of considering it to be 12. It is 0.12)
Now, we know that the answer should be a multiple of 0.12 since 'the remainder of s/t' will be equal to 'the remainder of s/t in decimal format' multiplied by 't'.
That is, R of (s/t) = 0.12*t ----> which is a multiple of 0.12 for all the positive integer values that 't' can hold.
Now, in order to make the calculation simpler, we can multiply both sides of the equation by 100.
R*100 = 12*t --> t = (R*100)/12
Now, since it is given that 't' is a positive integer, (R*100) has to be perfectly divisible by 12.
Thus look through the answer choices to see which one satisfies this condition.
You will find that R = 45 will be the only one that satisfies it, since 4500 is perfectly divisible by 12.
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