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complicated tables

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Manager
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complicated tables [#permalink] New post 18 Aug 2007, 14:10
Is there a simple strategy to solve questions that ask you to find total of a table with 7 rows and 7 columns

I cant draw a table here..

The table is like this
1 2 3 4 5 6 7
-2 -4 -6-8 -10- -12 -14.
.
.
.
.
.
7 14 ...................49
Manager
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 [#permalink] New post 18 Aug 2007, 14:27
There are some shortcut methods but they depend on the table...

Its not clear with the given table that what would be the 3rd line...

It requires more info...
Director
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Re: complicated tables [#permalink] New post 19 Aug 2007, 21:44
Sumithra Sen wrote:
Is there a simple strategy to solve questions that ask you to find total of a table with 7 rows and 7 columns

I cant draw a table here..

The table is like this
1 2 3 4 5 6 7
-2 -4 -6-8 -10- -12 -14.
.
.
.
.
.
7 14 ...................49






I am not sure but i think the series in each row looks like arithmatic progression we can use

sum = n( a1 + an) /2 for individual row and add it.
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 [#permalink] New post 19 Aug 2007, 22:01
this is from OG. I believe there is a certain pattern for each row. From there it would be easier to work out the sum.
Director
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Re: complicated tables [#permalink] New post 19 Aug 2007, 22:20
alpha_plus_gamma wrote:
Sumithra Sen wrote:
Is there a simple strategy to solve questions that ask you to find total of a table with 7 rows and 7 columns

I cant draw a table here..

The table is like this
1 2 3 4 5 6 7
-2 -4 -6-8 -10- -12 -14.
.
.
.
.
.
7 14 ...................49






I am not sure but i think the series in each row looks like arithmetic progression we can use

sum = n( a1 + an) /2 for individual row and add it.



I forgot to add that
for some rows we may need to apply the following formula

sum = n [ 2*a1 + (n-1) d]/ 2

n= num of terms
d = common differnce between 2 consecutive tems
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Re: complicated tables [#permalink] New post 20 Aug 2007, 00:09
Sumithra Sen wrote:
Is there a simple strategy to solve questions that ask you to find total of a table with 7 rows and 7 columns

I cant draw a table here..

The table is like this
1 2 3 4 5 6 7
-2 -4 -6-8 -10- -12 -14.
.
.
.
.
.
7 14 ...................49


If the sum of the first row is S, what are then sums of the other rows in terms of S?
Manager
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 [#permalink] New post 20 Aug 2007, 06:38
Note that each row is AP (at least the ones mentioned are). Hence the average of each row is the middle column (4th Column). The sum of each row = 7x(middle column)

Hence, sum of table = 7x(sum of all terms in middle column)

Hope this works in the given problem. OP, can you please provide OA?

best,
parsifal
  [#permalink] 20 Aug 2007, 06:38
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