Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

If |x| != |y|, xy != 0, x/(x+y) = n, and x/(x-y) = m, then x/y = ?

what i do is, equate the two x and solve

x/(x+y) = n, and x/(x-y) = m, - equation (0) x=nx+ny ; x=mx-my - equation (1)

on solving above x/y=(m+n)/(m-n) - equation (2)

i now substitute values for m and n (3,2) and find the value for x/y. The value turns out to be 5.

But when i substitute the same values in the answer choices, none of the them match.

However, if i substitute the values (say 2,3 again) of x and y in equation (0) and find the corresponding values of m and n, and then substitute the values of m and n in the answer choices, the answer matches the value of x/y that i had chosen(2/3).

Im not able to understand why the answers are not matching x/y when i substitute random values of m,n straightaway in equation (2) and why they do so wen i substitute the values of m,n derived from the substituted values of x,y in equation(0)

Can someone please help in trying me understand where i am going wrong .

ANSWER CHOICES a> 3m/2 b>3m/2n c>n(m+2)/2 d>2nm/(m-n) This is the right answer e>n^2-m^2/nm

If |x| != |y|, xy != 0, x/(x+y) = n, and x/(x-y) = m, then x/y = ?

what i do is, equate the two x and solve

x/(x+y) = n, and x/(x-y) = m, - equation (0) x=nx+ny ; x=mx-my - equation (1)

on solving above x/y=(m+n)/(m-n) - equation (2)

i now substitute values for m and n (3,2) and find the value for x/y. The value turns out to be 5.

But when i substitute the same values in the answer choices, none of the them match.

However, if i substitute the values (say 2,3 again) of x and y in equation (0) and find the corresponding values of m and n, and then substitute the values of m and n in the answer choices, the answer matches the value of x/y that i had chosen(2/3).

Im not able to understand why the answers are not matching x/y when i substitute random values of m,n straightaway in equation (2) and why they do so wen i substitute the values of m,n derived from the substituted values of x,y in equation(0)

Can someone please help in trying me understand where i am going wrong .

ANSWER CHOICES a> 3m/2 b>3m/2n c>n(m+2)/2 d>2nm/(m-n) This is the right answer e>n^2-m^2/nm

The problem is that you don't have independent values of m and n. These values are derived from the values of x and y. Depending on the values of x and y, we will get the values of m and n. Due to the relation between x/(x+y) and x(x-y), m and n cannot take every value.

Note that because m and n both depend on x and y, there will be certain relations between them. e.g. using each equation independently, you get x/y = n/(1 - n) x/y = m/(m - 1) Equating them, you get 2mn = m + n

When you take random values for m and n, these relations may not hold. So if you have to assume values, you have to assume values of the independent variables, not for the dependent variables.

So assume values for x and y and then proceed as shown below. Say x = 2, y = 1 x/(x+y) = n = 2/3, and x/(x-y) = m = 2 You get x/y = (m+n)/(m-n) = (2+2/3)/(2 - 2/3) = 2 Put m = 2 and n = 2/3 in the options. Option (D) gives you 2. _________________

If |x| != |y|, xy != 0, x/(x+y) = n, and x/(x-y) = m, then x/y = ?

what i do is, equate the two x and solve

x/(x+y) = n, and x/(x-y) = m, - equation (0) x=nx+ny ; x=mx-my - equation (1)

on solving above x/y=(m+n)/(m-n) - equation (2)

i now substitute values for m and n (3,2) and find the value for x/y. The value turns out to be 5.

But when i substitute the same values in the answer choices, none of the them match.

However, if i substitute the values (say 2,3 again) of x and y in equation (0) and find the corresponding values of m and n, and then substitute the values of m and n in the answer choices, the answer matches the value of x/y that i had chosen(2/3).

Im not able to understand why the answers are not matching x/y when i substitute random values of m,n straightaway in equation (2) and why they do so wen i substitute the values of m,n derived from the substituted values of x,y in equation(0)

Can someone please help in trying me understand where i am going wrong .

ANSWER CHOICES a> 3m/2 b>3m/2n c>n(m+2)/2 d>2nm/(m-n) This is the right answer e>n^2-m^2/nm

Well you are given,

\(\frac{x}{(x+y)} = n\), and \(\frac{x}{(x-y)} = m\),

First inverse the 2 equations, \(\frac{1}{n}\) = \(\frac{(x+y)}{x}\) \(\frac{1}{m}\) = \(\frac{(x-y)}{x}\)

What about this " If |x| != |y|, xy != 0, " why this was given

Regards,

lr

Yes, that's a good question. You should always analyze what the given data implies. It was necessary to give " If |x| != |y|, xy != 0, "

|x| != |y| implies that x is not equal to y. It also implies that x is not equal to -y. Note that we have x+y and x -y in the denominator. If either one of them is 0, the value of m or n will be undefined. Hence they need to give you that m and n have defined values. So x cannot be equal to y or -y.

Also we need to find the ratio of x/y. So y cannot be 0 either. xy != 0 implies that x is not 0 and y is not 0. So basically, they are telling us that values of m and n are defined and they are not 0. Also x/y is defined. _________________