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# Coordinate Geometry

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Senior Manager
Joined: 24 Mar 2011
Posts: 465
Location: Texas
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Kudos [?]: 74 [1] , given: 20

Coordinate Geometry [#permalink]  25 May 2011, 11:09
1
KUDOS
00:00

Difficulty:

(N/A)

Question Stats:

79% (01:44) correct 21% (01:46) wrong based on 15 sessions

In the diagram above, the line y = 4 is the perpendicular bisector of segment JK (not shown). What is the distance from the origin to point K ?

A. 4
B. 2sqrt(10)
C. 8
D. 6sqrt(2)
E. 4sqrt(34)
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Senior Manager
Joined: 03 Mar 2010
Posts: 446
Schools: Simon '16 (M)
Followers: 4

Kudos [?]: 150 [0], given: 22

Re: Coordinate Geometry [#permalink]  25 May 2011, 23:25
Refer to diagram:
Attachment:

SOLN.JPG [ 13.1 KiB | Viewed 1495 times ]

y=4 is perpendicular bisector of JK
Hence distance between Point J and line y = 6 = distance between line y and point K.
Point K(6,-2)
Distance between point K and origin is 6^2+2^2= 2\sqrt{10}

OA B.

Please let me know the OA.
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Posts: 1360
Followers: 13

Kudos [?]: 160 [0], given: 10

Re: Coordinate Geometry [#permalink]  25 May 2011, 23:40
coordinates of point k are (6,-2).
distance of J = 6 from y=4 means distance of 6 from y=4 for K gives y = -2.

thus 36+4 = distance from origin ^ 2
40 ^(1/2) = B
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Manager
Joined: 28 Jul 2011
Posts: 117
Followers: 0

Kudos [?]: 2 [0], given: 7

Re: Coordinate Geometry [#permalink]  03 Nov 2011, 12:15
Should be B. x^2= 2^2 + 6^2
Re: Coordinate Geometry   [#permalink] 03 Nov 2011, 12:15
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