m15q19: (6, 2) and (0, 6) are the endpoints of the diagonal

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Re: Math Challenge [#permalink]

25 Jul 2012, 03:54

KillerSquirrel wrote:

candice.chan wrote:

On the coordinate plance (6,2) and (0,6) are the endpoints of the diagonal of a square. What is the distance between point (0,0) and the closest vertext of the square?

a) 1/sqt(2)
b) 2
c) sqrt(2)
d) sqrt(3)
e) 2*sqrt(3)

Thx!

sorry to ask such a silly question , but can someone please explain how can it be a squere, if the coordinate on the endpoints of the diagonal of a square are (6,2) (0,6) ? dosen't it gives a rectangle area and not a square ?

thanks

Once one of the diagonals is given, your square is uniquely determined. The other diagonal bisects the first one and it is perpendicular to it.
And most important, the sides of the square should not necessarily be and are not (in this case) parallel to the axes.

Start and draw it: first connect the two points to get the first diagonal. Then take the middle of the line segment and draw a perpendicular to the given diagonal. Finally, take two points at equal distances from the middle point and such that the distance between them is the same as the length of the initial diagonal.
Now, you have all the vertices of your square.
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Re: m15q19: (6, 2) and (0, 6) are the endpoints of the diagonal [#permalink]

15 Feb 2013, 03:47

this is impossible to solve within 3 mins also in my opinion
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Re: m15q19: (6, 2) and (0, 6) are the endpoints of the diagonal [#permalink] 15 Feb 2013, 03:47

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m15q19: (6, 2) and (0, 6) are the endpoints of the diagonal

m15q19: (6, 2) and (0, 6) are the endpoints of the diagonal

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