Joined: 01 Jul 2010
Schools: LBS, Harvard, Booth, Stanford, ISB, NTU
WE 1: S/W Engineer
, given: 15
First consider the 3 couples each as single unit. Hence 3 couples can be arranged in 3! ways. And then for each of those 6 combination there are 8 ways in which individuals in a couple can be arranged.
Hence 6*8 = 48 ways.
A,B,C are 3 couples.
6 ways to arrange them is:
ABC BCA CBA
ACB BAC CAB
Now if a1a2, b1b2, c1c2 are the individuals, then they can be arranged in 8 ways:
Similar arrangements are possible for the rest of the 5 couple arrangements.
Am I right in my explanation???