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Joined: 01 Jul 2010
Posts: 53
Schools: LBS, Harvard, Booth, Stanford, ISB, NTU
WE 1: S/W Engineer
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Kudos [?]:
22
[0], given: 15

First consider the 3 couples each as single unit. Hence 3 couples can be arranged in 3! ways. And then for each of those 6 combination there are 8 ways in which individuals in a couple can be arranged. Hence 6*8 = 48 ways. Eg: A,B,C are 3 couples. 6 ways to arrange them is: ABC BCA CBA ACB BAC CAB Now if a1a2, b1b2, c1c2 are the individuals, then they can be arranged in 8 ways: a1a2,b1b2,c1c2 a2a1,b1b2,c1c2 a1a2,b2b1,c1c2 a2a1,b2b1,c1c2 a1a2,b1b2,c2c1 a2a1,b1b2,c2c1 a1a2,b2b1,c2c1 a2a1,b2b1,c2c1 Similar arrangements are possible for the rest of the 5 couple arrangements.
Am I right in my explanation???
