Hi, I remember there was a formula to count factors, but I can't find the notebook where I wrote it it.
If I recall correctly, you had to find all the prime factors, then turn them into base-exponents format, then drop the base, then add 1 to each exponents and then multiply them. Is this correct?
IE: Factors of 200?
(2)(2)(2)(5)(5), therefore: (2^3)(5^2),
(3+1)(2+1) = (4)(3) = 12
200 has 12 factors total.
Can someone confirm?
Yes that is correct !
Here s the formula
The number of divisors of a given number N(including 1 and the number itself)
where N= (a^m)(b^n)(c^m), where a,b,c are prime numbers ,are
for eg 70=(2^1)(5^1)(7^1)
Therefore, No of divisors= (1+1)(1+1)(1+1)=8
those would be 1,2,5,7,10,14,35,70
Hope thats clear !