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# Counting PS

Author Message
TAGS:
Director
Joined: 07 Jun 2004
Posts: 620
Location: PA
Followers: 2

Kudos [?]: 128 [0], given: 22

Counting PS [#permalink]  28 Nov 2010, 04:54
00:00

Difficulty:

5% (low)

Question Stats:

71% (01:32) correct 28% (01:32) wrong based on 14 sessions
Grace packed 5 pairs of shoes, 3 pairs of pants, 8 shirts, and 3 jackets for her business trip. If an outfit consists of one of each item of clothing except shirts, of which she will wear 2, how many different outfits can does Grace have available during her trip?

(A) 2,520
(B) 1,260
(C) 620
(D) 360
(E) 120
[Reveal] Spoiler: OA

_________________

If the Q jogged your mind do Kudos me : )

Manager
Joined: 02 Apr 2010
Posts: 103
Followers: 4

Kudos [?]: 89 [0], given: 18

Re: Counting PS [#permalink]  28 Nov 2010, 07:54
The idea is to multiply the number of possibilities for each item of clothing with the different items. For the shirts you essentially choose 2 out of 8 so you should use the combination forumla (don't know how to use math symbols here).

This gives you 5 x 3 x 28 x 3 = 1'260. Hence, solution B is correct.
Manager
Joined: 13 Jul 2010
Posts: 170
Followers: 1

Kudos [?]: 14 [0], given: 7

Re: Counting PS [#permalink]  28 Nov 2010, 19:38
5*3*(8!/2!((8-2)!)*3 = 5*3*28*3= 1260

Director
Joined: 03 Sep 2006
Posts: 893
Followers: 6

Kudos [?]: 83 [0], given: 33

Re: Counting PS [#permalink]  28 Nov 2010, 22:13
5*3*(8!/2!((8-2)!)*3 = 5*3*28*3= 1260
Re: Counting PS   [#permalink] 28 Nov 2010, 22:13
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