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Counting PS

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Director
Director
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Joined: 07 Jun 2004
Posts: 620
Location: PA
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Kudos [?]: 128 [0], given: 22

GMAT Tests User
Counting PS [#permalink] New post 28 Nov 2010, 04:54
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

71% (01:32) correct 28% (01:32) wrong based on 14 sessions
Grace packed 5 pairs of shoes, 3 pairs of pants, 8 shirts, and 3 jackets for her business trip. If an outfit consists of one of each item of clothing except shirts, of which she will wear 2, how many different outfits can does Grace have available during her trip?


(A) 2,520
(B) 1,260
(C) 620
(D) 360
(E) 120
[Reveal] Spoiler: OA

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Manager
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Joined: 02 Apr 2010
Posts: 103
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Kudos [?]: 89 [0], given: 18

Re: Counting PS [#permalink] New post 28 Nov 2010, 07:54
The idea is to multiply the number of possibilities for each item of clothing with the different items. For the shirts you essentially choose 2 out of 8 so you should use the combination forumla (don't know how to use math symbols here).

This gives you 5 x 3 x 28 x 3 = 1'260. Hence, solution B is correct.
Manager
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Joined: 13 Jul 2010
Posts: 170
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Re: Counting PS [#permalink] New post 28 Nov 2010, 19:38
5*3*(8!/2!((8-2)!)*3 = 5*3*28*3= 1260

answer is B.
Director
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Re: Counting PS [#permalink] New post 28 Nov 2010, 22:13
5*3*(8!/2!((8-2)!)*3 = 5*3*28*3= 1260
Re: Counting PS   [#permalink] 28 Nov 2010, 22:13
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