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VP
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Currently, y percent of the members on the finance committee [#permalink]
 08 Aug 2006, 12:21
Question Stats:
46% (06:01) correct
53% (02:12) wrong based on 1 sessions
Currently, y percent of the members on the finance committee are women and next month, z percent of the men on the finance committee will resign. If no other personnel changes occur, then after the resignations next month, the men who remain on the finance committee will represent what percent of the total finance committee members? A. (100)(100 - z)(100 - y) / 100^2 - z(100 - y) B. (100 - z)(100 - y) / 100 C. (100 - z)(100 - y) D. zy / 100 - z E. z(100 - y) / 100
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CEO
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Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008
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A
Current month:
Let total = 100
No. of females = y
No. of males = 100-y
Next month:
No of females = y
No of males = (100-y)*(100-z)/100
Total = y + (100-y)*(100-z)/100
= (100y + 100^2 - 100y -100z+yz)/100
= [100^2 - z(100-y)]/100
Percentage of males = [100 * (100-y)*(100-z)/100] / [100^2 - z(100-y)]/100
i.e (100)(100 – z)(100 – y)/100^2 – z(100 – y)
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SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008
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VP
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Re: PS: Finance committee [#permalink]
08 Aug 2006, 13:28
w = y
m = 100 - y
total = 100
m after z = (100 - y) - [z (100- y)/100] = (100-z)(100-y)/100
m (after z) as a % of total = [(100-z)(100-y)/100]/[{(100-y)(100-z)/100} + y] x [100]
after solviing for y and z: m (after z) as a % of total = [100 (100-z)(100-y)]/[(100^2 - z (100-y)]
its A. imo, plugging-in is best for such a tedious calculation.
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VP
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Re: PS: Finance committee [#permalink]
08 Aug 2006, 13:30
Professor wrote: its A. imo, plugging-in is best for such a tedious calculation.
agree... but took me 2.5 min to do so 
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VP
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Going with A...
tedious calculation for me... took more than 2 mins for sure.
At the end looked at the choices and picked A based on how it looked compared to my results.
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Manager
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Arrived safely at (A), but I agree that clalculations are tedious...
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Manager
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ps_dahiya wrote: A
Current month:
Let total = 100
No. of females = y
No. of males = 100-y
Next month:
No of females = y
No of males = (100-y)*(100-z)/100
Total = y + (100-y)*(100-z)/100
= (100y + 100^2 - 100y -100z+yz)/100
= [100^2 - z(100-y)]/100
Percentage of males = [100 * (100-y)*(100-z)/100] / [100^2 - z(100-y)]/100
i.e (100)(100 – z)(100 – y)/100^2 – z(100 – y)
Ps: How are you getting 100-z/100 when Q says z% of the men. Wouldnt it be (100-y)*z/100
Heman
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Manager
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heman wrote: ps_dahiya wrote: A
Current month:
Let total = 100
No. of females = y
No. of males = 100-y
Next month:
No of females = y
No of males = (100-y)*(100-z)/100
Total = y + (100-y)*(100-z)/100
= (100y + 100^2 - 100y -100z+yz)/100
= [100^2 - z(100-y)]/100
Percentage of males = [100 * (100-y)*(100-z)/100] / [100^2 - z(100-y)]/100
i.e (100)(100 – z)(100 – y)/100^2 – z(100 – y) Ps: How are you getting 100-z/100 when Q says z% of the men. Wouldnt it be (100-y)*z/100 Heman z pct men left, so the number of remaining men is 100-z pct of women.
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SVP
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For these questions..... I find it better to take some values for y and z
for example.
Let total finance commitee members = 100
Let y = 20 and z = 5
hence men left = 80 - 4 = 76
Percent = 7600/96
Now lets plug in values in the choices.
A = 100 * 95*80/10000 - 400
= 100 * 95*80/9600
= 7600/96
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Magoosh GMAT Instructor
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Re: Currently, y percent of the members on the finance committee [#permalink]
18 Apr 2012, 15:46
Hi, I know this is an ancient thread  but was just replying in response to one of Magoosh's users who had asked me to take a look. The responses above are fine (check out ps-dahiya's). The thing with this problem is the algebraic solution is time-consuming and unwieldy. It is not that the users are missing a more elegant algebraic solution. The take away from a question such as this one - esp., if you want to answer it in under 2 minutes - is to plug in. @Jaynayak shows how to do so in his post. Hope that helps  .
_________________
Christopher Lele
Magoosh Test Prep
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Re: Currently, y percent of the members on the finance committee
[#permalink]
18 Apr 2012, 15:46
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